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Anestetic [448]
3 years ago
15

A red light source emits light of a certain frequency. A violet light source emits light that has double the frequency of the re

d light source. How does the wavelength of the red light compare to the violet light.
Chemistry
2 answers:
romanna [79]3 years ago
8 0

Answer:

a

Explanation:

zloy xaker [14]3 years ago
4 0

The wavelength of red light is double the wavelength of violet light.

<h3>Explanation:</h3>

Let n_R = Frequency of red light source

Let n_V = Frequency of violet light source

Let λR = Wavelength of red light source

Let λV = Wavelength of violet light source

Given: Frequency of violet light is two times (double) the frequency of red light.

Therefore n_V = 2\times n_R ........................(1)

The relation between speed of light (c), frequency (n) and wavelength (λ) is given by

c = nλ

<em>Frequency is inversely proportional to λ.</em>

The speed of light remains constant for both light sources = c = 3 × 10⁸ m/s²

For red light source: c = n_R\times λR  ........................(2)

For violet light source: c = n_V\times λV ..................(3)

Equating (2) and (3), we get

c= n_R\times λR = n_V \times λV

From (1)

n_R\times λR = 2\times n_R\times λV

λR = 2 × λV

Therefore, wavelength of red light is two times the wavelength of violet light.

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How is a mixture such as a plate of pasta different from a mixture such as air
stealth61 [152]

Answer:

Well there is a lot of differences between the two. Its called homogeneous and Heterogeneous mixtures. Homogeneous mixtures are all the substances are evenly distributed throughout the mixture (salt water, air, blood).  Heterogeneous mixtures are the substances that are not evenly distributed (chocolate chip cookies, pizza, rocks). So Pasta with sauce and meatballs is heterogeneous and air is homogeneous




HOPE THIS HELPS HAVE A GREAT DAY!!~

Explanation:

6 0
2 years ago
Identify the independent variable, dependent variable, and constant in the following problem: If you plant hydrangeas in your ga
Afina-wow [57]
The independent variable is the one you change, and the dependent variable is the one that changes because the independent changed (i think). The constant variable is the thing you can't change so the experiment is fair.

Independant: whatever causes the flowers to change color 
Dependent: the flowers change color
Constant: same soil type, same conditions, etc.
5 0
3 years ago
Read 2 more answers
What volume of 0.194 MNa3PO4 solution is necessary to completely react with 85.5 mL of 0.109 MCuCl2 ?
ira [324]

Answer:

35.9 ml

Explanation:

Start with the balanced equation:

3CuCl2(aq)+2Na3PO4(aq)→Cu3(PO4)2(s)+6NaCl(aq)

This tells us that 3 moles of CuCI2 react with 2 moles Na3PO4-

∴  1 mole CuCl2 will react with 2/3 moles Na3PO4

We know that concentration = moles/volume i.e:

c= n/v

∴n=c×v

∴nCuCl2=0.107×91.01000=9.737×10−3

I divided by 1000 to convert ml to L

∴nNa3PO4=9.737×10−3×23=6.491×10−3

v=nc=6.491×10−30.181=35.86×10−3L

∴v=35.86ml

4 0
2 years ago
What did the periodic table help scientists discover?
Monica [59]
They discovered that *elements* show increase in atomic numbers across the period.
8 0
3 years ago
Read 2 more answers
You determine the volume of your plastic bag (simulated human stomach) is 1.08 L. How many grams of NaHCO3 (s) are required to f
dsp73

Answer:

3.636 grams of sodium bicarbonate is required.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 753.5 mmHg = 0.9914 atm

(1 atm = 760 mmHg)

V = Volume of gas = 1.08 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 24.5 °C= 297.65  K

Putting values in above equation, we get:

(0.9914 atm)\times 1.08 L=n\times (0.0821L.atm/mol.K)\times 297.65K\\\\n=0.0438 mole

Percentage recovery of carbon dioxide gas =  49.4%

Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole

\frac{49.4}{100}\times  0.0438 mol=0.02164 mol

2NaHCO_3\righarrow Na_2CO_3+H_2O+CO_2

According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.

Then 0.02164 moles f carbon dioxide will be obtained from:

\frac{2}{1}\times 0.02164 mol=0.04328 mol

Mass of 0.04328 moles pf sodium bicarbonate:

0.04328 mol × 84 g/mol = 3.636 g

3.636 grams of sodium bicarbonate is required.

5 0
3 years ago
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