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Anestetic [448]
3 years ago
15

A red light source emits light of a certain frequency. A violet light source emits light that has double the frequency of the re

d light source. How does the wavelength of the red light compare to the violet light.
Chemistry
2 answers:
romanna [79]3 years ago
8 0

Answer:

a

Explanation:

zloy xaker [14]3 years ago
4 0

The wavelength of red light is double the wavelength of violet light.

<h3>Explanation:</h3>

Let n_R = Frequency of red light source

Let n_V = Frequency of violet light source

Let λR = Wavelength of red light source

Let λV = Wavelength of violet light source

Given: Frequency of violet light is two times (double) the frequency of red light.

Therefore n_V = 2\times n_R ........................(1)

The relation between speed of light (c), frequency (n) and wavelength (λ) is given by

c = nλ

<em>Frequency is inversely proportional to λ.</em>

The speed of light remains constant for both light sources = c = 3 × 10⁸ m/s²

For red light source: c = n_R\times λR  ........................(2)

For violet light source: c = n_V\times λV ..................(3)

Equating (2) and (3), we get

c= n_R\times λR = n_V \times λV

From (1)

n_R\times λR = 2\times n_R\times λV

λR = 2 × λV

Therefore, wavelength of red light is two times the wavelength of violet light.

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Anything with mass creates gravity, but the amount of gravity is proportional to the amount of mass.
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Answer:

Explanation:

The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects. Gravity is a force that increases the velocity of falling objects - they accelerate.

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3 years ago
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Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of c
Anna [14]

The question is incomplete. The complete question is

Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of calcium nitrate. A double displacement reaction occurs. What mass of each of the following substances is present when the reaction stops. A) potassium phosphate remaining B) calcium nitrate g remaining C) calcium phosphate formed D) potassium nitrate g formed

Answer:

a)84.91g

b)8.20g

c)316.4g

d)616.73g

Explanation:

The equation of the reaction:

2K3PO4(aq) + 3Ca(NO3)2 (aq)-------> 6KNO3(aq) + Ca3(PO4)2(s)

Molar mass of potassium phosphate= 212.27 g/mol

Amount of potassium phosphate= 500/212.27= 2.4 moles

Molar mass of calcium nitrate= 164.088 g/mol

Amount of calcium nitrate= 500/164.088=3.05moles

a) amount of potassium phosphate reacted according to reaction equation= 2 moles

Amount of potassium phosphate remaining= 2.4-2=0.4 moles

Mass of potassium phosphate remaining= 0.4×212.27=84.91g

b) Amount of calcium nitrate reacted according to reaction equation=3

Amount of calcium nitrate remaining=3.05-3= 0.05

Mass of calcium nitrate remaining= 0.05×164.088= 8.20g

c) since calcium nitrate is the limiting reactant, we use to estimate the mass of products formed.

From the reaction equation,

3 moles of calcium nitrate yields 1 mole of calcium phosphate

3.05 moles of calcium nitrate yields 3.05/3 = 1.02 moles of calcium phosphate

Molar Mass of calcium phosphate= 310.18 g/mol

Mass of calcium phosphate produced= 1.02×310.18= 316.4g

d)

3 moles of calcium nitrate yields 6 moles of potassium nitrate

3.05 moles of calcium nitrate yields 3.05×6/3= 6.1 moles of potassium nitrate

Molar mass of potassium nitrate = 101.1032 g/mol

Mass of potassium nitrate formed= 6.1× 101.1032= 616.73g

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d(glucose) = 1,02 g/ml.
d(water) = 1,00 g/ml.
Specific gravity of glucose = density of glucose ÷ density of water.
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