Is a potential to provide effective treatment with fewer side effects than a traditional therapy.
In the compound iodine heptafluoride: (hints: write out the molecular formula of this compound before answering the question. Also be sure you clearly understand the concepts of charge, oxidation numbers, how to determine charge and oxidation numbers, and - most important of all! - the similarities and the differences between charges and oxidation numbers)
<u>Each fluorine atom has a charge of 1</u>
<h3>What is
iodine heptafluoride?</h3>
The interhalogen compound iodine heptafluoride, often known as iodine(VII) fluoride or iodine fluoride, has the chemical formula IF7. As anticipated by VSEPR theory, it exhibits a unique pentagonal bipyramidal structure. The molecule is capable of undergoing the Bartell process, a pseudorotational rearrangement that is similar to the Berry mechanism but for a heptacoordinated system. It produces colorless crystals that melt at 4.5 °C and have a very narrow liquid range with a boiling point of 4.77 °C. The dense mist has an unpleasant, musty smell. The molecule is symmetrical with D5h. suggestion
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The empirical formula is XeO₃.
<u>Explanation:</u>
Assume 100 g of the compound is present. This changes the percents to grams:
Given mass in g:
Xenon = 73.23 g
Oxygen = 26.77 g
We have to convert it to moles.
Xe = 73.23/
131.293 = 0.56 moles
O = 26.77/ 16 = 1.67 moles
Divide by the lowest value, seeking the smallest whole-number ratio:
Xe = 0.56/ 0.56 = 1
O = 1.67/ 0.56 = 2.9 ≈3
So the empirical formula is XeO₃.
The required volume of water is 0.18 liters.
<h3>What is molarity?</h3>
Molarity of any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V
Moles of solute will be calculated as:
n = W/M, where
W = given mass of HCl = 32g
M = molar mass of HCl = 36.4g/mol
n = 32 / 36.4 = 0.88 mole
Given molarity of solution = 4.80M
On putting all values in the above equation, we get
V = (0.88) / (36.4) = 0.18 L
Hence required volume of water is 0.18L.
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