If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2
so .611 moles
so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams
so first ans is .611 moles and second is 34.7 grams !
if you have any problem regarding this , just comment !!!
Explanation:
(a) The given data is as follows.
Pressure on top (
) = 140 bar = 
(as 1 bar = 
)
Temperature = 
= (15 + 273) K = 288 K
Density of gas = 
= 0.4548
= 
= 
Hence, pressure at the natural gas-oil interface is .
(b) At the bottom of the tank,
= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]
= 
= 309.8 bar
Hence, at the bottom of the well at pressure is 309.8 bar.
Answer:
The answer is True.
Explanation:
The sentence above is true it all adds up.
Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below
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