a sample of a gas has a volume kf 640 cm^{3} at 100°c and 1490 mmhg,what would be its volume at stp?
1 answer:
Answer:
V₂ = 918.1 cm³
Explanation:
Given data:
Initial volume = 640 cm³
Initial temperature = 100°C (100+273 = 373 K)
Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)
Final volume = ?
Final temperature = 273 K
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm
V₂ = 342451.2 atm .cm³ . K / 373 K. atm
V₂ = 918.1 cm³
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