Answer:
Type: M
Name: Dixytrogen Pentasulfide
Molar Mass:
X*2 = Number * 2 = Number
S*5=32.066*5=160.33
Number + 160.33 = Molar Mass (g/mol).
(The mass for Xytrogen is not present).
Explanation:
Assuming Xytrogen is a non-metal and bonding it with sulfur, another non-metal would make it covalent or molecular.
The name is from the amount of Xs (being two [Di]) and the amount of Ss (being five [Penta]).
The molar mass is explained above. You need to multiply the mass of each element by the number of elements present in the compound. The mass for Xytrogen is not present (as it is a made up element) so I left instructions how to do it once given the mass instruction.
Hope this helps.
Answer:
5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.
Explanation:
The balanced reaction:
CO (g) + 2 H₂ (g) -> CH₃OH (l)
By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:
- CO: 1 mole
- H₂: 2 moles
- CH₃OH: 1 mole
Being the molar mass of each compound:
- CO: 28 g/mole
- H₂: 1 g/mole
- CH₃OH: 32 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- CO: 1 mole* 28 g/mole= 28 grams
- H₂: 2 moles* 1 g/mole= 2 grams
- CH₃OH: 1 mole* 32 g/mole= 32 grams
Being 6 kg equivalent to 6000 grams (1 kg= 1000 grams), you can apply the following rules of three:
- If by stoichiometry 32 grams of methanol are formed from 28 grams of carbon monoxide, 6000 grams of methanol are formed from how much mass of carbon monoxide?

mass of carbon monoxide= 5250 grams= 5.25 kg
If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?

mass of hydrogen= 375 grams
<u><em>5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol. </em></u>
Answer:
Decrease
Explanation:
The lower you go, the colder because the sun can't reach lower levels of the ocean.