0.02 g of calcium carbonate (CaCO₃)
Explanation:
To solve the question we use the Avogadro's number using the following reasoning:
if 1 moles of calcium carbonate contains 6.022 × 10²³ units of calcium carbonate
then X moles of calcium carbonate contains 12.044 × 10²³ units of calcium carbonate
X = (1 × 12.044 × 10²³) / 6.022 × 10²³ = 2 moles of calcium carbonate
mass = number of moles × molecular weight
mass of calcium carbonate (CaCO₃) = 2 / 100 = 0.02 g
Learn more about:
Avogadro's number
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No because the deviation from the theoretical value is quite high and the temperature range of your sample is too wide.
Answer:
decomposers
Explanation:
I'm not sure weather your supposed to create an actual experiment or write a paper. If an experiment, test certain acids to see which one can decompose plastics the fastest and determine which one can be spread through the oceans to melt down plastic. If a paper, discuss the idea of genetically modified fish. Some animals in the wild have the ability to eat pollution (wrappers, bottles, ect.), so mutating fish such as bottom feeders to be able to do the same would easily rid the water of pollution and make for one interesting of a paper! hope this sort of helped!
Answer:
to put it simply, equilibrium is when two opposing forces balance each other out. one example is boats: you know how the bottom half is curved, and then meets at an edge? they design it like that because of water displacement. by gravity, the water wants to go back to the area taken by the boats mass (the parts where it has sunken into the water), thus preventing the boat from sinking. once the boat is removed, the water returns to the space. most liquids take form of their container.
The compound : C₄₀H₄₄N₄O
<h3>Further explanation</h3>
The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
• Determine the mass ratio of the constituent elements of the compound.
• Determine the mole ratio by dividing the percentage by the atomic mass
The mol ratio of composition : C : H : N : O
