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Andrei [34K]
3 years ago
10

Be sure to answer all parts.Classify each nitrogen-containing functional group in the anesthetic lidocaine according to whether

it is an amide, or a primary, secondary, or tertiary amine.h542140Functional group 1 is a(n) .Functional group 2 is a(n)

Chemistry
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

The 1st functional group is secondary amine and the 2nd fun. group is tertiary amine.

Explanation:

Lidocaine does not contain amide functional group in its composition as nitrogen is associated only with carbon.

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Determine the mass of 10g of CaCO3​
NISA [10]

Answer:

= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u

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An enzyme is a catalyst used by living things to promote and regulate chemical reactions. What is the most likely enzyme for the
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I’m going to guess but B?
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Calculate the kinetic energy of a baseball (mass = 5.25 oz) with a velocity of 1.0 x 10^2 mi/h
pychu [463]

Answer:

262.5 Joules

Explanation:

You find the kinetic energy of multiplying half of the mass by the velocity. In this word problem it tells you the mass so you divide it by 2. That answer is 2.625, you then multiply that by the velocity, in this instance it's 1.0 x 10^2 mi/h.

The unit in kinetic energy is Joules. This is actually a really important part in chemistry and physics.

5 0
2 years ago
You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0
3 years ago
The ionization of pure water forms _____.
Evgesh-ka [11]

Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

H_2O+H_2O\rightleftharpoons H_3O^++OH^-

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

4 0
3 years ago
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