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2 years ago

Which of the following is an advantage of using biopower?

Chemistry

2 answers:

zavuch27 [327]2 years ago

8 0

Answer: Option (C) is the correct answer.

Explanation:

Biopower means production of electricity with the help of biomass. The unused wood, crops, agricultural residue, animal residue etc when burned then they help in generating biopower.

It is a renewable energy. Since biomass is readily available in most of the places. Therefore, the advantage of biopower is that it is also readily available in most places.

For example, bacterial decay produces a certain amount of heat which further helps in the production of energy.

denpristay [2]2 years ago

4 0

Answer:

The correct answer is option C. It is readily available in most places.

Explanation:

Hi!

Let's solve this!

The biopower is obtaining energy from renewable energies. More specifically, from biomass. Biomass is the organic matter that is a waste. The use of this biomass, turning it into energy, is the biopower.

As it is organic matter, it is found anywhere. For example, wood from trees, agricultural waste, livestock waste, among others.

We conclude that the correct answer is option C. It is readily available in most places.

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The name of the METAL in an ionic compounds does not change<br><br> True or False

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This is a true statement.

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3 years ago

If one mole of an unknown substance is 200.59 g/mole, what is the mass of 0.33 moles of that substance?

Nesterboy [21]

Answer: 66.83g

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0.33 moles = 66.83g

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2 years ago

Convert 1.5 mol Na to mass

Elina [12.6K]

Answer:

19.49

Explanation:

1.5 times the mass of Na which is 12.99 is 19.485

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2 years ago

How many moles of nitrogen are needed to produce 1.20 moles of ammonia gas?

liubo4ka [24]

Answer:

0.6moles

Explanation:

Check attachment

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3 years ago

The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C

Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})$

$1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})$

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})$

$1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})$

T₂=371.77 K= 98.62 °C

5 0

2 years ago