2C3H7OH + 9O2 → 6CO2 + 8H2O
Answer: m = 24.31 g/mol · 1.13 mol
Explanation: 2 mol HCl use 1 mol Mg.
Magnesium is used 0.5 · 2.26 mol = 1.13 mol
M(Mg) = 24.31 g/ mol
Answer:
The percentage efficiency of the electrical element is approximately 82.186%
Explanation:
The given parameters are;
The thermal energy provided by the stove element,
= 3.34 × 10³ J
The amount thermal energy gained by the kettle,
= 5.95 × 10² J
The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

Therefore, we get;

The percentage efficiency of the electrical element, η% ≈ 82.186%.