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dimulka [17.4K]
4 years ago
15

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and th

at if events are mutually exclusive they must be independent. Do you agree with this statement
Mathematics
1 answer:
beks73 [17]4 years ago
8 0

Answer:

No, Mutually exclusive events and Independent events are not the same.

Step-by-step explanation:

Mutually exclusive events and Independent events are not the same.

  • Mutually Exclusive Events:

Mutually exclusive events are those events that cannot occur together, i.e. they cannot take place at the same time.

For example, the events of tossing a Head and Tails are mutually exclusive. This is because when a coin is flipped it cannot land on both sides at once.

  • Independent Events:

Independent events are those events that can occur at the same time without affecting each other, i.r. they are not dependent on the occurrence of other events in the sample space.

For example, on rolling two fair die the events of first die rolling 4 and the second die rolling 1 are independent.

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For rhombus A:
base = 7 in
area = 35 in²

Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in

Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²

Area of rhombus B is 9 times area of rhombus A. When the dimensions are increased to 3 times the initial dimension, area became 9 times.

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4 years ago
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in one day angie can make two dresses or three blouses or four skirts. how long will it take her to make the clothes to fill her
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3 years ago
Given sintheta =7/11 and sectheta is less than 0, find costheta and tantheta
Korvikt [17]

Answer:

Step-by-step explanation:

Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane.  If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2.  Remember that sec theta is the inverse of cos theta.  Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11.  In order to find the cos theta and tan theta, we need the side adjacent to the angle.  Use Pythagorean's Theorem to find the side adjacent.

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121=47+x^2 and

72=x^2 so

x=6\sqrt{2}

Remember that this value is why the sec is negative.  Because x is negative in QII, the cos theta is side adjacent over hypotenuse:

cos\theta=-\frac{6\sqrt{2} }{11}  and

tan\theta=-\frac{7}{6\sqrt{2} }

But we should probably rationalize that denominator, so

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You sent 118 texts that month
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3 years ago
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The vertex form:\ y=a(x-p)^2+q\ where\ (p;\ q)-coordinates\ of\ the\ vertex

The range of function y=ax^2+bx+c

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4 years ago
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