Thank you for posting your question your question here. Below is the solution:
time = 3.00 / 1.75
<span>time = 1.714 </span>
<span>now </span>
<span>distance = (initial velocity + final velocity) / 2 * time/ 1 </span>
<span>Hence</span>
<span>3 = ( 1.75 + final velocity) / 2 * 1.714 </span>
<span>3.5 - 1.75 = final velocity </span>
<span>Therefore, the final velocity is 1.75 m /s</span>
To get the speed of light in this class glass, used the following equation
v= c/n ; where c is the speed of light in a vacuum and n where the index of refraction
Based on my research the index of refraction of the class glass is 1.59
Given
c= 3.00 x 10^8 m/s
n= 1.59
Solution
we will use 3.00 for c to get the speed of light in class glass cause 10^8 m/s is fixed
v= 3.00 / 1.59
v= 1.886
So the speed of light in this class glass is 1.89 x 10^8 m/s
Answer:
Sometimes may cause involuntary responses like twitching
Explanation:
Answer:
r=0.127
Explanation:
When connected in series
Current = I
When connected in parallel
Current = 10 I
We know that equivalent resistance
In series R = R₁+R₂
in parallel R= R₁R₂/(R₂+ R₁)
Given that voltage is constant (Vo)
V = I R
Vo = I (R₁+R₂) ------------1
Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2
From above equations
10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)
10 R₁R₂ = (R₁+R₂) (R₂+ R₁)
10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²
8 R₁R₂ = R₁² + R₂²
Given that
r = R₁/R₂
Divides by R₂²
8R₁/R₂ = ( R₁/R₂)²+ 1
8 r = r ² + 1
r ² - 8 r+ 1 =0
r= 0.127 and r= 7.87
But given that R₂>R₁ It means that r<1 only.
So the answer is r=0.127