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Anna007 [38]
4 years ago
11

Which factors improve soil fertility? Select the three correct answers.

Physics
3 answers:
horrorfan [7]4 years ago
7 0
B. Bacteria
C.Earthworms 
D. Humus
@CristianoRonaldo
nirvana33 [79]4 years ago
7 0

Answer: The correct answer is- B) bacteria, C) Earthworm, and D) Humus.

Out of the given options, bacteria, Earthworms, and Humus helps in improving the fertility of soil.

Bacteria and Earthworms can decompose the organic matter and convert it into usable form for plant's growth. They also help in enhancing the amount of air and water in the soil so that it can be efficiently utilized by plants. Humus is an organic material that is dark in color and rich in nutrients as it is obtained by the decay of plant and animal matter. It helps in sustaining moisture in the soil and by providing nutrients, it makes the soil fertile.

Thus, B), C), and D) is the right answer.



Snowcat [4.5K]4 years ago
3 0

Answer: The correct answer is- B) bacteria, C) Earthworm, and D) Humus.


Out of the given options, bacteria, Earthworms, and Humus helps in improving the fertility of soil.

Bacteria and Earthworms can decompose the organic matter and convert it into usable form for plant's growth. They also help in enhancing the amount of air and water in the soil so that it can be efficiently utilized by plants.



Humus is an organic material that is dark in color and rich in nutrients as it is obtained by the decay of plant and animal matter. It helps in sustaining moisture in the soil and by providing nutrients, it makes the soil fertile.


Thus, B), C), and D) is the right answer.



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Why are lighter cars allowed to drive on motorways at higher speeds than heavier ones?
daser333 [38]

Answer:

say a lighter car is going 80mph and a heavier car is going the same speed who do you think will have more damage i will say the heavier car

Explanation:

3 0
3 years ago
A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 w
vlada-n [284]

Answer:

(a) 1/60

(b) Yes, it was unusual.

Explanation:

Number that went to the right field = 19

Number that went to the right center field = 18

Number that went to the center field = 12

Number that went to the left center field = 10

Number that went to the left field = 1

Total number of home runs = 60

(a) The probability that a randomly selected home run was hit to left ​field is

P(left field) = 1/60

(b) It was unusual because whenever a player hit a home run, it most times went to the right field,which is why the right field had the highest probability, 19/60.

On the other hand, it went to the left field the least number of times, which is why the left field had the least probability, 1/60.

So, it was unusual.

5 0
3 years ago
A radio-controlled car increases its kinetic energy from 3 J to 10 J over a distance of 1 m. What was the average net force on t
goldfiish [28.3K]

Answer:

Net force, F = 7 N

Explanation:

It is given that,

Initial kinetic energy of the car, K_i=3\ J

Final kinetic energy of the car, K_f=10\ J

Distance, d = 1 m

We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :

W=\Delta K

W=K_f-K_i

Also, W = F.d    d = distance and F = net force

F.d=K_f-K_i

F=\dfrac{K_f-K_i}{d}

F=\dfrac{10\ J-3\ J}{1\ m}

F = 7 Newton

So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.

8 0
3 years ago
look at picture, need to know net force, whether they are balanced or unbalanced and whether they are accelerated or not acceler
AlexFokin [52]

Not a clear pic sorry i can't help

3 0
3 years ago
Your target variable is δf, the magnitude of the difference in frequency between the waves emitted from the sonar device and the
Mars2501 [29]

Answer:

  f´ = f (v ±v₀) / (v ⁻₊ v_{s})

Explanation:

This is a doppler effect exercise that is the change of frequency by the relative speed of the emitter and receiver of sound

For the first part, the sound comes out of the sounding device, which is generally removed, so the speed of the emitter is vs = 0 and the receiver (the whale) is moving, so the equation is

               f ”= f ((v ± v₀) / v)

where the sign plus (+) corresponds to the observer moving towards the source that is at rest, f is the frequency emitted by the probe and f” the frequency received by the whale.

In the second part, the waves are reflected by the whale, which becomes the emitter and the receiver that is the probe remains at rest, so the expression is

               d´ = d ”(v / (v ⁻₊ v_{s}))

where the least succor for the source moving towards the observer,

Therefore, the frequency received by the probe (f´) is

              f´ = f ((v ±-v₀) / v) (v / v⁻₊ v_{s}))

              f´ = f (v ±v₀) / (v ⁻₊ v_{s})

3 0
4 years ago
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