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Rzqust [24]
3 years ago
9

A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required

Physics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

4N

Explanation:

a = (7-3)/5 = 0.8m/s^2

F = ma = (5)(0.8) = 4 Newtons

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Explanation the third one for the second question

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A solid object has a density of 2.85 g/cm3. According to Archimedes, what can be done to make this object float in water?
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4 0
3 years ago
True or False. A material with randomly oriented atoms is magnetic.
Alexeev081 [22]

Answer:true

Explanation:

because atoms is what makes it able for things to be picked up

7 0
3 years ago
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Define 1 unit electricity​
Tomtit [17]

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4 0
3 years ago
In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst
Archy [21]

Answer:

16 cm

Explanation:

For protons:

Energy, E = 300 keV

radius of orbit, r1 = 16 cm

the relation for the energy and velocity is given by

E = \frac{1}{2}mv^{2}

So, v = \sqrt{\frac{2E}{m}}   .... (1)

Now,

r = \frac{mv}{Bq}

Substitute the value of v from equation (1), we get

r = \frac{\sqrt{2mE}}{Bq}

Let the radius of the alpha particle is r2.

For proton

So, r_{1} = \frac{\sqrt{2m_{1}E}}{Bq_{1}}    ... (2)

Where, m1 is the mass of proton, q1 is the charge of proton

For alpha particle

So, r_{2} = \frac{\sqrt{2m_{2}E}}{Bq_{2}}    ... (3)

Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle

Divide equation (2) by equation (3), we get

\frac{r_{1}}{r_{2}}=\frac{q_{2}}{q_{1}}\times \sqrt{\frac{m_{1}}{m_{2}}}

q1 = q

q2 = 2q

m1 = m

m2 = 4m

By substituting the values

\frac{r_{1}}{r_{2}}=\frac{2q}}{q}}\times \sqrt{\frac{m}}{4m}}=1

So, r2 = r1 = 16 cm

Thus, the radius of the alpha particle is 16 cm.

8 0
3 years ago
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