Step-by-step explanation:
we have two lines you have to draw.
one is all in the bottom left quadrant (for x<=0) and one in the upper right quadrant (for x>5).
the easiest is for x>5. the line function is only
f(x) = y = 3
so, this is a horizontal line on the grid line for y = 3. it starts above x=5 and then goes all the way to the right ("to infinity and beyond !"). just, if possible, mark the starting point at x=5 as a little empty "circle" instead of a full dot, as x=5 is explicitly excluded (due to x>5).
and for x<=0 the line
f(x) = y = 4x - 3
goes sharp down but goes a little bit to the left the further down it goes. it starts with x=0, which gives y=-3 per the function.
so, the starting point (with a full dot, as x=0 is included) is (0,-3).
from there it goes sharp down and a little bit to the left.
for example the next point is for x=-1, which gives y=-7, so it is the point (-1,-7). x=-2 gives y=-11 and the point (-2,-11).
the line has to go through so these points and further down (again, "to infinity and beyond !"), as to move further left on the negative x-axis.
Answer:
Step-by-step explanation:
We want to evaluate:
When x=0, we obtain the first term of the geometric series as
The common ratio of this geometric series is
The sum of the first n-terms of a geometric series is
From x=0 to x=15, we have 16 terms.
The sum of the first 16 terms of the geometric series is
to the nearest tenth.
Y= 8x-9, because I need more characters