Answer:
%age Yield = 96 %
Explanation:
The balance chemical equation for given double replacement reaction is,
Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃
Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>
Moles = Mass / M.Mass
Moles = 75.1 g / 261.33 g/mol
Moles = 0.2873 moles of Ba(NO₃)₂
Step 2: <u>Find out moles of BaSO₄ formed:</u>
According to balance chemical equation,
1 mole of Ba(NO₃)₂ produced = 1 mole of BaSO₄
So,
0.2873 moles of Ba(NO₃)₂ will produce = X moles of BaSO₄
Solving for X,
X = 0.2873 mol × 1 mol / 1 mol
X = 0.2873 moles of BaSO₄
Step 3: Calculate Theoretical Mass of BaSO₄:
Mass = Moles × M.Mass
Mass = 0.2873 mol × 233.38 g/mol
Mass = 67.07 g of BaSO₄
Step 4: <u>Calculate %age Yield as:</u>
Theoretical Yield = 67.07 g
Actual Yield = 64.4 g
%age Yield = <u>???</u>
Formula Used:
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
Putting Values,
%age Yield = (64.4 g ÷ 67.07 g) × 100
%age Yield = 96.01 % ≈ 96 %
<span>a. the orbital is defined by n,L, mL so (n, L, mL, -1), (n, L,mL, 0) and (n,L,mL, +1) and 3 electrons for any given orbital
b. in (n,L,mL,ms) format the first 12 elements would look like this
(1, 0, 0, +1)
(1, 0, 0, 0)
(1, 0, 0, -1)
(2, 0, 0, +1)
(2, 0, 0, 0)
(2, 0, 0, -1)
(2, 1, 0, +1)
(2, 1, 1, +1)<-----ANSWER
(2, 1, 0, 0)
(2, 1, 1, 0)
(2, 1, 0, -1)
(2, 1, 1, -1)
the idea is we don't pair up electrons until all the mL's have 1 so we wouldn't write
(2, 1, 0, +1)
(2, 1, 0, 0)
(2, 1, 0, -1)
then.
(2, 1, 1, +1)
(2, 1, 1, 0)
(2, 1, 1, -1)
because they would fill
(2, 1, 0, +1)1st
(2, 1, 0, 0)3rd
(2, 1, 0, -1)5th
then.
(2, 1, 1, +1)2nd
(2, 1, 1, 0)4th
(2, 1, 1, -1)6th
to pair (or rather triple up) electrons last
c. ideal gases are when each n level is full...
(1, 0, 0, +1)
(1, 0, 0, 0)
(1, 0, 0, -1)<----- ideal gas 3 electrons so 3 protons and atomic # = 3
(2, 0, 0, +1)
(2, 0, 0, 0)
(2, 0, 0, -1)
(2, 1, 0, +1)
(2, 1, 1, +1)
(2, 1, 0, 0)
(2, 1, 1, 0)
(2, 1, 0, -1)
(2, 1, 1, -1)<----- 2nd ideal gas12 e's so 12 p's and atomic # = 12
continuing on
(3, 0, 0, +1)
(3, 0, 0, 0)
(3, 0, 0, -1)
(3, 1, 0, +1)
(3, 1, 1, +1)
(3, 1, 0, 0)
(3, 1, 1, 0)
(3, 1, 0, -1)
(3, 1, 1, -1)..
(3, 2, 0, +1)
(3, 2, 1, +1)
(3, 2, 2, +1)
(3, 2, 0, 0)
(3, 2, 1, 0)
(3, 2, 2, 0)
(3, 2, 0, -1)
(3, 2, 1, -1)
(3, 2, 2, -1)<--- 3rd nobel gas atomic # = 30
hope it helps
</span>
Answer:
Keto - enol tautomerism
Explanation:
Phenolphthalein is an organic molecule (formula: C20H14O4), which is used in to determine the final volume in an acid-base titration, this is, as the molecule changes from one to another color, depending on the Ph of the solution (in acids solution, the molecule remains colorless, while in basics solutions it remains pink) :
The molecule of phenolphthalein is a week acid, which losses a proton (H+) when it´s in solution: the undissociated molecule is colorless, while the correspondent anion (without a H+) is pink. This may be simplified with the following reaction:
H₃In⁺ ⇄ H₂In (colorless) ⇄ In⁻² (pink) ⇄ In(OH) ⁻³
- When adding a base (for example, NaOH) to phenolphthalein (initially, a colorless solution), molecule losses one H⁺ and we obtain In⁻², which is pink
- When adding an acid, the original structured is recovered, so color turns from pink to colorless
This change color is not only explained with adding an acid or a base, but also with phenolphthalein structure, that leads to a keto-enol tautomerism: as molecule has 2 hydroxyl groups (- OH) and 1 carbonyl group (C = O), compounds with this structure have an equilibrium between both groups:
R1 = C H– OH ⇄ R1 – C = O
With this change, phenolphthalein structure changes and hence, color solution changes as well
