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Elodia [21]
3 years ago
12

During a lab experiment, Mandy and her lab partner work with corrosive chemical substances. What is the proper way to dispose of

these chemicals after the lab is completed?
Chemistry
1 answer:
Mandarinka [93]3 years ago
8 0
They would have to dispose them in their designated waste bin/container the instructor assigned.

You NEVER dispose of chemicals down the drain.
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Look at the picture ​
Ronch [10]

Answer:

The strong electric force.

Explanation:

Trust me. If its wrong, comment on this, don't delete it. If someone else answers with the wrong question than other students might get the answer wrong. So if its right, say that it is, if its wrong, tell others what the real answer is.

3 0
2 years ago
How many millimeters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3
KonstantinChe [14]
<span>So we need 0.276 moles of HCl to react. Your concentration is given in moles/liter so 0.276/1.58 = 0.174 liters needed or 174 milliliters</span>
8 0
3 years ago
Read 2 more answers
A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
larisa86 [58]

Explanation:

The given reaction is as follows.

        HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Hence, number of moles of NaOH are as follows.

        n = 0.05 L \times 0.1 M

           = 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

             n = 0.025 L \times 0.1 M

                = 0.0025 mol

According to ICE table,

         HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Initial:     0.005 mol   0.0025 mol              0                  0

Change: -0.0025 mol  -0.0025 mol        +0.0025 mol

Equibm:   0.0025 mol    0                         0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

          [HA] = \frac{0.0025 mol}{V}

        [NaA] = \frac{0.0025 mol}{V}

       [A^{-}] = [NaA] = \frac{0.0025 mol}{V}

Now, we will calculate the pK_{a} value as follows.

          pH = pK_{a} + log \frac{A^{-}}{HA}

       pK_{a} = pH - log \frac{[A^{-}]}{[HA]}

                  = 3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}

                  = 3.42

Thus, we can conclude that pK_{a} of the weak acid is 3.42.

           

8 0
3 years ago
How many molecules are their in o.5 mole of H2o
Black_prince [1.1K]

Answer:

There are 6.022x10^23 molecules

3 0
3 years ago
Naming compounding<br> N2O
solniwko [45]

Answer:

Nitrogenous oxide/ nitrogen oxide

Explanation:

N2O is nitrogen oxide

6 0
2 years ago
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