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ladessa [460]
3 years ago
14

Prove dimensionally that: PV=RT

Physics
1 answer:
Oduvanchick [21]3 years ago
4 0

Ideal Gas Law PV = nRT

THE GASEOUS STATE
Pressure  atm
Volume  liters
n  moles
R  L atm mol^-1 K^-1
Temperature  Kelvin


pv = rt

divide both sides by v
pv/v = rt/v

p = rt/v

answer: p = rt/v




Ideal Gas Law: Density

PV = NRT
PV = mass/(mw)RT

mass/V = P (MW)/RT = density



Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV


Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.

Total = P_ A + P_ B

P_ A V = n_ A RT

P_ B V = n_ B R T



Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV

P_ total = P_ A + P_ B = n_ total RT/V




For Ideal Gasses:


P_ A = n_ A RT/V P_ total = n_ toatal RT/V



P_ A/P_ total = n_ A RTV/n_ total RTV


= n_ A/n_ total = X_ A





Therefore, P_ A = X_ A P_ total.



PV = nRT


P pressure

V volume


n Number of moles


R Gas Constant


T temperture (Kelvin.).







Hope that helps!!!!!! Have a great day : )

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Answer:

Heat energy needed = 3036.17 kJ

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We have

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     heat of vaporization of water = 2257 J/g

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Here wee need to convert 1 kg ice from -13°C to vapor at 100°C

First the ice changes to -13°C from 0°C , then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

Mass of water = 1000 g

Heat energy required to change ice temperature from -13°C to 0°C

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Heat energy required to change ice from 0°C to water at 0°C

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Heat energy required to change water temperature from 0°C to 100°C  

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Heat energy required to change water from 100°C to steam at 100°C  

          H₄ = mL = 1000 x 2257 = 2257 kJ    

Total heat energy required

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Pls someone I need it urgently and explain Solving and explanation so I can understand Thank you
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Answer:

   f = 6.37 Hz,       T = 0.157 s

Explanation:

The expression you have is

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