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krok68 [10]
3 years ago
11

Block A is also connected to a horizontally-mounted spring with a spring constant of 281 J/m2. What is the angular frequency (in

rad/s) of simple harmonic oscillations of this system?
Physics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula to be used here is

ω = 2π/T

Where ω is the angular frequency (in rad/s)

T is the period - the time taken for Block A to complete one oscillation and return to it's original position.

To solve for this period T, the formula below should be used

T = 2π√m/k

where m is the mass of the object (Block A) and k is the spring constant (281 J/m²)

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The smallest scale of the following is
Llana [10]

Answer:

B) 1:100

Explanation:

this explanation is actually simple.

you can see this problem as a simple comparation if you move for example

1:10

if you move 1 cm you are going to move 10cm  in the other side usually is used for planes in architecture or sizing issues, so, if the scale need to be grater, that is if is necessary to increase the number inthe right side in this case 10 cm to 100cm it is because in 100 the resolution is better.

you can see this problem as a fraction

1/10 or 1/1000

4 0
3 years ago
A parallel-plate capacitor with plates of area 360 cm2 is charged to a potential difference V and is then disconnected from the
Softa [21]

Answer:

Q=3.9825\times 10^{-9} C

Explanation:

We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.

1 m =100 cm

Surface area =S=\frac{360}{10000}=0.036 m^2

\Delta d=0.8 cm=0.008 m

\Delta V=100 V

We have to find the charge Q on the positive plates of the capacitor.

V=Initial voltage between plates

d=Initial distance between plates

Initial Capacitance of capacitor

C=\frac{\epsilon_0 S}{d}

Capacitance of capacitor after moving plates

C_1=\frac{\epsilon_0 S}{(d+\Delta d)}

V=\frac{Q}{C}

Potential difference between plates after moving

V=\frac{Q}{C_1}

V+\Delta V=\frac{Q}{C_1}

\frac{Qd}{\epsilon_0S}+100=\frac{Q(d+\Delta d)}{\epsilon_0S}

\frac{Q(d+\Delta d)}{\epsilon_0 S}-\frac{Qd}{\epsilon_0S}=100

\frac{Q\Delta d}{\epsilon_0 S}=100

\epsilon_0=8.85\times 10^{-12}

Q=\frac{100\times 8.85\times 10^{-12}\times 0.036}{0.008}

Q=3.9825\times 10^{-9} C

Hence, the charge on positive plate of capacitor=Q=3.9825\times 10^{-9} C

6 0
4 years ago
A Canadian driving from Quebec to Montreal finds he has traveled 271 km. How many miles is this? There are 1.61 km in 1 mi
kotegsom [21]

Answer:

168.32 mile

Explanation:

1 mile = 1.61 km

1.61 km = 1 mile

1 km = 1 / 1.61 mile

So, 271 km = 271 / 1.61 = 168.32 mile

3 0
3 years ago
Which statements describe a physical property of matter? Check all that apply
Galina-37 [17]
<span>The correct answer is all mentioned because all have the characteristics that apply in theories of the properties of matter and their physical behaviors, which encompass mass, temperature, smell, and volume.</span>
5 0
4 years ago
Read 2 more answers
According to the concept of length contraction, what happens to the length of an object as it approaches the speed of light and
lord [1]
When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.
8 0
4 years ago
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