Answer: Tension = 53.6N
Explanation:
Given that
Height h = 1 m
Time t = 1.7 s.
Mass m = 5.1 kg
From the equation of the motion we can get the acceleration of the elevator:
h = X0+ V0t + at2/2;
Th elevator starts from rest with a constant upward acceleration. Initial velocity Vo = 0, also Xo = 0; thus
a = 2h/t2 = 2 × 1/1.7^2
a = 0.69 m/s2.
Then we can find the tension in the cord by using the formula
T = mg + ma
= 5.1 (9.8 + 0.69)
= 5.1 × 10.5
= 53.6N
Answer:
(a) 1.093 rad/s^2
(b) 4.375 rad/s
(c) 8.744 rad/s
(d) 67.845 rad
Explanation:
initial angular velocity, ωo = 0
time, t = 8s
angular displacement, θ = 35 rad
(a) Let α be the angular acceleration.
Use second equation of motion for rotational motion

By substituting the values
35 = 0 + 0.5 x α x 8 x 8
α = 1.093 rad/s^2
(b) The average angular velocity is defined as the ratio of total angular displacement to the total time taken .
Average angular velocity = 35 / 8 = 4.375 rad/s
(c) Let ω be the instantaneous angular velocity at t = 8 s
Use first equation of motion for rotational motion
ω = ωo + αt
ω = 0 + 1.093 x 8 = 8.744 rad/s
(d) Let in next 5 seconds the angular displacement is θ.

By substituting the values
θ = 8.744 x 5 + 0.5 x 1.093 x 5 x 5
θ = 67.845 rad
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