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sweet [91]
3 years ago
5

Physics help please ;-; . An astronaut has a mass of 82.0 kg. What is the astronaut's stationary weight at a position 4230 kilom

eters above Earth's surface? Note: Earth's radius is 6380 km and the Earth's mass is 5.972 x 1024 kg.
Two rocks, each of mass 72 kg, are positioned 95 m away from each other in deep space. What is the magnitude of the gravitational attraction between them?

if at the least explain how id work it out.​
Physics
1 answer:
sweet [91]3 years ago
3 0

Answer:

F = G*\frac{m_{1} * m_{2} }{r^2}

Explanation:

Just find the force of gravity.

1) m1 is the mass of earth, m2 is mass of astronaut. r is the earth's radius + astronaut's position in meters. G is the universal constant of gravity.

2) Same as above. m1 is 72 kg, m2 is 72 kg, r is 95 m and G is gravitational constant.

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8 0
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Oscilloscope amplitude and frequency problem. Study the above graph. The volts/div dial is set to 2 volts/div and the time/div d
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Answer:

Amplitude = 8 Volts

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Explanation:

Note: The missing picture in question is attached for your review.

Given:

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Time/Div = 5 msec/div

Finding Amplitude:

Now, as you can see in the attached picture, there are 4 division between two peaks of the waveform, so,

Amplitude = 4 div/volts * 2 volts/ div )\\Amplitude = 8 Volts

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Finding Frequency:

As can be seen in attached picture, 3 division are there for one complete cycle of waveform,so,

Time Period = 3 div * 5msec /div\\Time Perod = 15 msec

Since,

Frequency = \frac{1}{Time Period}\\Frequency = \frac{1}{15m}\\Frequency = 0.067 kHz

8 0
3 years ago
A ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s. If the radius of the ride is 9.0 meters, what is
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8 0
3 years ago
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