Let f(x) = x^2-5x-6 and g(x) f(t)dt find the critical points of g(x) g

The top of an off shore oil rig has an elevation of 199.2 m and its base has an elevation of -9.6 m and observation deck is loca

matrenka [14]

Answer: 57.6m

Step-by-step explanation:

That's a lot of words that questions usually use to try to trip us up but not this time so lets pull all relevant information

199.2m= top of off shore oil rig

-9.6 m is the base of the rig

observation deck is 1/6 of the total height

helly pad is 22.8m above the observation deck

First lets try to find the total height of the rig. We can do this by adding the absolute value of the top and base of the oil rig. So 199.2 + 9.6 = 208.8m

So the total height is 208.8m now lets find the observation deck. We know the observaition is 1/6 of the total height which is 208.8m right so lets multiply. 1/6*208.8m= 34.8m

Now we know the observation deck is 34.8m high. Finally we can find the helly pad which is 22.8 m above the observation deck.

Since the observation deck is 34.8m and the helly pad is 22.8 above observation deck (34.8m) all we have to do is add so 22.8+34.8= 57.6m

So we know the total height is 208.8m

The observation deck is 34.8m

And the helly pad is 57.6m

7 0

3 years ago

The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

Maurinko [17]

The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
 area = 19.3138746047 

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / 1.65684 
area = 173.824871442 

 173.824871442 / 19.3138746047 = 9

So, the area would be 9 times larger.

ALSO, looking at the formula
n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

5 0

4 years ago

A rocket launches upward off of a 18 ft platform with an initial velocity of 125 ft/sec creating the equation begin mathsize 18p

Dmitry_Shevchenko [17]

Um i this is not my level

6 0

3 years ago

a 28 ft. ladder leaning against a vertical wall makes an angel of 80 degrees with the ground. How far from the base of the wall

worty [1.4K]

Answer:

The ladder is 4.86 foot from the base of the wall .

Step-by-step explanation:

Given as :

The length of the ladder = 28 ft

The ladder makes angle of 80° with the ground

Let The distance of the ladder from the foot of the wall = x ft

Now, From Triangle BAC

Cos angle = $\dfrac{\textrm Base}{\textrm Hypotenuse}$

I.e Cos 80° = $\dfrac{\textrm BA}{\textrm AC}$

Or, 0.1736 = $\dfrac{\textrm x}{\textrm 28}$

Or, x = 0.1736 × 28

∴ x = 4.86 foot

So, The distance of ladder from wall base = x = 4.86 foot

Hence The ladder is 4.86 foot from the base of the wall . Answer

3 0

3 years ago

At a pizza eating competition, Davonne ate four more than twice as many slices as the runner up. If Davonne ate 11 slices, then

Sauron [17]

Let's begin with x as the number of slices the runner up ate.
Davonne ate four more than twice
So the equation should look somewhat like this.
4+2x=11
2x=7
x=3.5
So the runner up ate 3.5 slices
Davonne ate four more than twice as many slices as the runner up. If Davonne ate 11 slices, then how many slices did the runner up eat?

3 0

3 years ago