All categories

3 years ago

True or false ? Radiant energy is generated by a petunia on Tuesday.

Physics

2 answers:

Fudgin [204]3 years ago

7 0

It is true that radiant energy or is generated by a petunia

Leya [2.2K]3 years ago

4 0

The answer is true that Radiant energy is generated by a petunia on Tuesday

You might be interested in

How does Newton's three laws of motion apply to the egg drop project

BabaBlast [244]

Newtons First Law is applied on my egg experiment because it will not move or change it's acceleration until a force acts upon it. Newton's Second Law is applied because of the acceleration caused by natural forces as the egg is plummeting to the earth. And the amount of acceleration the egg has will be largely affected by the amount of force used to hurl the egg to the ground. The Third Law of Motion affects the egg because the amount of force the egg hits the ground with, the ground pushes back with equal and opposite force.

4 0

3 years ago

Read 2 more answers

In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second project

Trava [24]

Answer:

Second projectile is 1.4 times faster than first projectile.

Explanation:

By linear momentum conservation

Pi = Pf

m x U + M x 0 = (m + M) x V

$U= \dfrac{(m + M)\times V}{m}$

Now Since this projectile + pendulum system rises to height 'h', So using energy conservation:

KEi + PEi = KEf + PEf

PEi = 0, at reference point

KEf = 0, Speed of system zero at height 'h'

$KEi = \dfrac{(m + M)\times V^2}{2}$

PEf = (m + M) g h

So,

$\dfrac{(m + M)\times V^2}{2} + 0 = 0+ (m + M) g h$

$V =\sqrt {2gh}$

So from above value of V

Initial velocity of projectile =U

$U=\dfrac{(M+m)\sqrt{2gh}}{m}$

Now Since mass of projectile and pendulum are constant, So Initial velocity of projectile is proportional to the square root of height swung by pendulum.

Which means

$\dfrac{U_2}{U_1}=\sqrt{\dfrac{h_2}{h_1}}$

$U_2=\sqrt{\dfrac{h_2}{h_1}}\times U_1$

$U_2=\sqrt{\dfrac{5.2}{2.6}}\times U_1$

U₂ = 1.41 U₁

Therefore we can say that ,Second projectile is 1.4 times faster than first projectile.

4 0

3 years ago

Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un

Lena [83]

Answer: $316.8V$

Explanation:

given data:

metre moving current = $0.96mA$

meters voltage = $288V$

or $0.96*300V = 288V$

Solution:

$v1 = (0.96mA*150)$

$= 144V$

$i1 = \frac{144v}{750}$

$= 0.192mA$

$i2 = imovement + i1$

$i2= 0.96mA+0.192mA$

$= 1.152mA$

$Vmeasured = 144V+(150)(1.152mA)$

$=316.8V$

the unknown voltage is 316.8V

7 0

3 years ago

A skater is spinning at 15.0 rad/s with a rotational inertia of 8.0 kg m? If she changes her rotational inertia to 5.0 kg mº, wh

mixas84 [53]

Answer:Idrk man

Explanation:

3 0

2 years ago

A student is considering doing a complete repeated measures design experiment involving motor skills. The student's advisor has

Lelu [443]

Answer:

c. ABBA counterbalancing 

Explanation:

The student should not use the method because it is a progressive error management technique for each subject by introducing all treatment circumstances twice, first in one sequence, then in the other (AB, BA) by subject counterbalancing.

If participants experience conditions more than once, they experience the conditions first in one order, then the opposite order.

3 0

3 years ago