Complete Question
The complete question is shown on the uploaded image
Answer:
The tension on the shank is ![T =8391.6 N](https://tex.z-dn.net/?f=T%20%3D8391.6%20N)
Explanation:
From the question we are told that
The strain on the strain on the head is ![\Delta l = 0.1 mm/mm = \frac{0.1}{1000} = 0.1 *10^{-3} m/m](https://tex.z-dn.net/?f=%5CDelta%20l%20%3D%200.1%20mm%2Fmm%20%3D%20%5Cfrac%7B0.1%7D%7B1000%7D%20%3D%200.1%20%2A10%5E%7B-3%7D%20m%2Fm)
The contact area is
Looking at the first diagram
At 600 MPa of stress
The strain is ![0.3mm/mm](https://tex.z-dn.net/?f=0.3mm%2Fmm)
At 450 MPa of stress
The strain is ![0.0015 mm/mm](https://tex.z-dn.net/?f=0.0015%20mm%2Fmm)
To find the stress at
we use the interpolation method
![\frac{\sigma_{\Delta l} - \sigma_{0.0015} }{ \sigma _ {0.3} - \sigma_{0.0015} } = \frac{e_{\Delta l } - e_{0.0015}}{e_{0.3} - e_{ 0.0015}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csigma_%7B%5CDelta%20l%7D%20-%20%20%5Csigma_%7B0.0015%7D%20%7D%7B%20%5Csigma%20_%20%7B0.3%7D%20-%20%5Csigma_%7B0.0015%7D%20%7D%20%3D%20%5Cfrac%7Be_%7B%5CDelta%20l%20%7D%20%20-%20e_%7B0.0015%7D%7D%7Be_%7B0.3%7D%20-%20e_%7B%200.0015%7D%7D)
Substituting values
![\frac{\sigma _{\Delta l} - 450}{600 - 450} = \frac{0.1 -0.0015}{0.3 - 0.0015}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csigma%20_%7B%5CDelta%20l%7D%20-%20450%7D%7B600%20-%20450%7D%20%3D%20%5Cfrac%7B0.1%20-0.0015%7D%7B0.3%20-%200.0015%7D)
![\sigma _{\Delta l} -450 = 49.50](https://tex.z-dn.net/?f=%5Csigma%20_%7B%5CDelta%20l%7D%20-450%20%3D%2049.50)
![\sigma _{\Delta l} = 499.50 MPa](https://tex.z-dn.net/?f=%5Csigma%20_%7B%5CDelta%20l%7D%20%3D%20499.50%20MPa)
Generally the force on each head is mathematically represented as
![F = \sigma_{\Delta l} * A](https://tex.z-dn.net/?f=F%20%3D%20%5Csigma_%7B%5CDelta%20l%7D%20%2A%20A)
Substituting values
![F = 499.50*10^{6} * 2.8*10^{-6}](https://tex.z-dn.net/?f=F%20%3D%20499.50%2A10%5E%7B6%7D%20%2A%202.8%2A10%5E%7B-6%7D)
![=1398.6N](https://tex.z-dn.net/?f=%3D1398.6N)
Now the tension on the bolt shank is as a result of the force on the 6 head which is mathematically evaluated as
![T = 6 * F](https://tex.z-dn.net/?f=T%20%3D%206%20%2A%20F)
![= 6* 1398.6](https://tex.z-dn.net/?f=%3D%206%2A%201398.6)
![T =8391.6 N](https://tex.z-dn.net/?f=T%20%3D8391.6%20N)
Answer:
The volume of 3200 kg of petrol is 4 m^3.
Answer:
D 9.8 m/s^2
Explanation:
The force of gravitational gravity on earth is 9.8 m/s^2
Answer:
If the radio wave is on an FM station, these are in Megahertz. A megahertz is one ... Typical radio wave frequencies are about 88~108 MHz .
Explanation:
To calculate the wavelength of a radio wave, you will be using the equation: Speed of a wave = wavelength X frequency.
Since radio waves are electromagnetic waves and travel at 2.997 X
10
8
meters/second, then you will need to know the frequency of the radio wave.
If the radio wave is on an FM station, these are in Megahertz. A megahertz is one million hertz. If the radio wave is from an AM radio station, these are in kilohertz (there are one thousand hertz in a kilohertz). Hertz are waves/second. Hertz is usually the label for the frequency of electromagnetic waves.
To conclude, to determine the wavelength of a radio wave, you take the speed and divide it by the frequency.
Typical radio wave frequencies are about
88
~
108
MHz
. The wavelength is thus typically about
3.41
×
10
9
~
2.78
×
10
9
nm
.
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30
E = 350 * 30
E = 1050 Joules.
So, your answer is 1050 Joules.
Hope this helps! Keep studying!