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lianna [129]
3 years ago
10

Jenna flips a 10p coin four times. Here are her results:

Physics
1 answer:
ValentinkaMS [17]3 years ago
6 0

Answer:

Option B

Explanation:

The reliability of an experiment can be increased by conducting experiment sufficient number of times keeping other things constant. Hence, the 10 p coin needs to be flipped again to measure reliability for more than one times.

Hence, option B is correct

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Can somebody help please !!!!
Nataly [62]

Vector A is of magnitude 12 m and it makes an angle of 37 degree with Y axis

So here we can say that

\frac{A_x}{A} = sin37

A_x = A sin37

A_x = 12 sin37

A_x = 7.22 m

Similarly we have

\frac{A_y}{A} = cos37

A_y = A cos37

A_y = 12 cos37

A_y = 9.58 m

So here we have

A_y = 9.58 m, A_x = 7.22 m

option A is correct

3 0
3 years ago
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
How does the thickness of a planets atmosphere affect a planets average temperature
scZoUnD [109]

Answer:

Hey

The thickness of a planet's atmosphere determines the tempature. the reason why is because gas traps or reflects light. Gass molecules generally reflect light which means that photons bounce of gass molecules. But the space between these molecules allows most of the light to travel through and hit the   planet.

4 0
3 years ago
A light wave travels through water (n = 1.33) at an angle of 35°. What angle
Dovator [93]

Answer:1

Explanation:

1

4 0
3 years ago
Read 2 more answers
What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?
olya-2409 [2.1K]

Weight = (mass) x (acceleration of gravity)

Acceleration of gravity = 9.81 m/s² on Earth, 1.62 m/s² on the Moon.

The feather's weight is . . .

On Earth:  (0.0001 kg) x (9.81 m/s²) = <em>0.000981 Newton </em>

On the Moon:  (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference.  In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup.  Weight is just the force of gravity between the feather and the Earth.  It's not affected by what's around the feather, or what's happening to it.

6 0
3 years ago
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