Question

A 2 x106 kg rocket is launched from the surface of the Earth What is the escape speed in km/s) of the rocket with respect to its gravitational interaction with the Sun? The intial distance of the rocket from the Sun s 150 x1o!1m and the mass of the Sun is 1.99 x 1030 kg You may ignoreal other gravitational ntoractions for the rocket and assume r gravitational interactions for the rocket and assume that the system is isolated

Answer 1

Answer:

Escape speed of the rocket, v = 4206.86 m/s

Explanation:

Mass of the rocket, $m=2\times 10^6\ kg$

We need to find the escape speed of the rocket with respect to its gravitational interaction with the Sun. It is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

Where

G is the universal gravitational constant

R is the distance

$v=\sqrt{\dfrac{2\times 6.67\times 10^{-11}\times 1.99\times 10^{30}}{150\times 10^{11}}}$

v = 4206.86 m/s

So, the escape speed of the rocket is 4206.86 m/s. Hence, this is the required solution.