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shutvik [7]
3 years ago
6

A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What

is the speed of the 6.0 kg object after the collision
Physics
1 answer:
RSB [31]3 years ago
4 0
V_2' = v_1 + v_1'
So v_2' = 40 + -25
We have set east to be + and west -
Which gives us 15 m/s. So thats how fast the 6 kg object is going.
This is true for an elastic collision.
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A total lunar eclipse is:
Igoryamba

Answer:

B) Visible to all observers on the night time side of the earth

Explanation:

I hope this helps.

8 0
2 years ago
A solenoid 27.0 cm long and with a cross-sectional area of 0.600 cm2 contains 440 turns of wire and carries a current of 90.0 A.
11Alexandr11 [23.1K]

Answer:

(A) 0.1842 T (B) 1.3507\times 10^{-4}J/m^3 (C) 0.2188 J (D) 5.40\times 10^{-5}H

Explanation:

Length of the solenoid L = 27  cm =0.27 m

Area of cross section A=0.6\ cm^2=0.6\times 10^{-4}m^2

Number of turns N = 440

Current i = 90 A

(A) Magnetic field in the solenoid B=\mu _0ni=\frac{\mu _0Ni}{l}=\frac{4\pi \times 10^{-7}\times 440\times 90}{.27}=0.1842\ T

(B) The energy density is given by energy\ density =\frac{B^2}{2\mu _0}=\frac{0.1842^2}{2\times 4\pi \times 10^{-7}}=1.3507\times 10^4\ j/m^3

(C) The total energy contained in the coli magnetic field = energy density ×volume = energy density ×l×A

So the total energy =1.3507\times 10^4\times 0.27\times 0.6\times 10^{-4}=0.2188\ j

(D) The energy stored in the inductor is given by U=\frac{1}{2}Li^2

So L=\frac{2U}{i^2}=\frac{2\times 0.2188}{90^2}=5.40 \times 10^{-5}H

7 0
3 years ago
Which describes the phenotype of the tomato plant
blagie [28]
The allele for red skin is dominant R
The allele for yellow skin is recessive r
The genotype Rr is heterozygous, resulting in phenotype: red skin tomato
The genotype RR is dominant homozygous, resulting in phenotype: red skin tomato
The genotype rr is recessive homozygous, resulting in phenotype: yellow skin tomato

Read more on Brainly.com - brainly.com/question/10183300#readmore
4 0
3 years ago
Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
Sedaia [141]

Answer:

a_2\ =\ -33.65\ m/s^2

Explanation:

Given,

For the first rocket,

  • Initial velocity of the first rocket A = u_1\ =\ 4600\ m/s.
  • Acceleration of the first rocket = a_1\ =\ -18\ m/s^2

For the second rocket,

  • Initial velocity of the second rocket B = u_2\ =\ 8200 m/s.
  • Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec

Let a_2 be the acceleration of the second rocket B for the same time interval

from the kinematics,

\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\

\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0
3 years ago
An object traveling a circular path of radius 5 m at constant speed experiences an acceleration of 3 m/s2. If the radius of its
Alina [70]
........The answer is B
7 0
3 years ago
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