If an object travels at a constant speed in a circular path, the acceleration of the object is:
1 answer:
Answer:
1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.
Explanation:
The acceleration of an object in a circular path is
As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.
As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.
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Answer:
(a) Acceleration of electron= 5.993×10²⁰ m/s²
(b) Acceleration of proton= 3.264×10¹⁷ m/s²
Explanation:
Given Data
distance r= 6.50×10⁻¹⁰ m
Mass of electron Me=9.109×10⁻³¹ kg
Mass of proton Mp=1.673×10⁻²⁷ kg
Charge of electron qe= -e = -1.602×10⁻¹⁹C
Charge of electron qp= e = 1.602×10⁻¹⁹C
To find
(a) Acceleration of electron
(b) Acceleration of proton
Solution
Since the charges are opposite the Coulomb Force is attractive
So
From Newtons Second Law of motion
F=ma
a=F/m
For (a) Acceleration of electron
For(b) Acceleration of proton