If an object travels at a constant speed in a circular path, the acceleration of the object is:
1 answer:
Answer:
1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.
Explanation:
The acceleration of an object in a circular path is
As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.
As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.
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Answer:
The height is : 60.025 m
Explanation:
The flowerpot falls off the balcony with zero launch angle
Given the time of fright as 3.5 s then ;
The formula to apply is ;
3.5²= 2H/9.8
12.25 =2H/9.8
12.25 * 9.8 = 2H
120.05 = 2H
120.05/2 = H
60.025 =H
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We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.
We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.