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evablogger [386]
3 years ago
9

Four students measured the acceleration of gravity. The accepted value for their location is 9.78 m/s2. Which student's measurem

ent has the largest percent error?
Physics
2 answers:
garri49 [273]3 years ago
6 0
<span>the answer would actually be student 1 :9.87 m/s2, not 9.78</span>
Vitek1552 [10]3 years ago
4 0

Answer:

9.45m/s^2

Explanation:

I just took the quiz and if you have options "9.85, 9.45, 10.01, 9.75" 9.45m/s^2 is the correct option.

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If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?
Licemer1 [7]
<h2>It takes 6.78 seconds to complete 12 dribbles.</h2>

Explanation:

Frequency of dribble = 1.77 Hz

That is

         Number of dribbles in 1 second = 1.77

         \texttt{Time taken for 1 dribble = }\frac{1}{1.77}=0.565s

Now we need to find how long does it take for you to complete 12 dribbles.

         Time taken for 12 dribbles = 12 x Time taken for 1 dribble

         Time taken for 12 dribbles = 12 x 0.565

         Time taken for 12 dribbles = 6.78 seconds      

It takes 6.78 seconds to complete 12 dribbles.  

8 0
3 years ago
According to “The Cyclone,” who invented the Fourth of July?
Vilka [71]
<span>A. Pecos Bill 

</span>According to “The Cyclone,” who invented the Fourth of July is PECOS BILL
NOT:
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8 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
hodyreva [135]

Answer : The correct option is, (c) 3.7\times 10^2J/^oC

Explanation :

First we have to calculate the energy or heat.

Formula used :

E=V\times I\times t

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

E=(3.6V)\times (2.6A)\times (350s)

E=3276J

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}

where,

C = heat capacity of the calorimeter

T_{initial} = initial temperature = 20.3^oC

T_{final} = final temperature = 29.1^oC

Now put all the given values in this formula, we get:

C=\frac{3276J}{(29.1-20.3)^oC}

C=372.27J/^oC=3.7\times 10^2J/^oC

Therefore, the heat capacity of the calorimeter is, 3.7\times 10^2J/^oC

7 0
3 years ago
What happens to an iron bar when it is placed within the coils of a solenoid
Rina8888 [55]
When the iron bar is placed within the coils of a solenoid it then becomes a magnet.  
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The crate would slide forward
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