In an undeveloped country, the rural areas will often be off the grid, with no access to consistent electricity. For a household living in this situation, <u>wood</u> would most likely be used to heat the home in the winter.
<u>Explanation:</u>
With the help of wood, we can burn it and make fire to heat the house in winter. In the earlier days, wood was used to produce heat and was used for cooking and other purposes.
So when a rural area does not have electricity,stoves would be fired with either biomass fuels, such as wood, branches, twigs or dung, or coal. Also for heating the home, the same would be used. These fuels are collected from the local environment in rural areas and purchased through markets in urban areas. Even now in some countries like India and China use wood or any other biomass fuel for heating and cooking.
Answer: 0.0138 m^2 = 138 cm^2
Explanation:
The thermal expansion is the term use for the physical phenomena of dilation of the objects when they are exposed to changes in temperature.
The objects dilate when they are heated and contract when they are cooled.
The dilation is proportional to the change in temperatur.
For linear dilation, the proportionality constant is called linear dilation coefficient of the materials, it is named α and is measured in °C ^-1.
ΔL = α * Lo * ΔT, which means that the dilation (or contraction) is proportional to the product of the original length (Lo) and the change of temperature (ΔT).
There is also superficial dilation, for which the dilation is:
ΔA = β * Ao * ΔT, which means that the superficial dilation (or contraction) is proportional to the product of the original area (Ao) and the change of temperature (ΔT).
It is very interesting and important to solve problems that β = 2α, because regularly you will find the values of α for different materials and so, you just to multiply it times 2 to use β.
For this problem:
- Original area, Ao = area of the flat roof at - 10°C = 2.0m * 3.0m = 6.0 m^2.
- α for aluminum = 24 * 10^ -6 °C^-1.
- ΔT = 38°C - (-10°C) = 48°C
So, ΔA = 6.0m^2 * (2 * 24*10^-6 °C&-1) * 48°C = 0.0138 m^2
And that is the area that should stick out in summer to fit the structure during cold winter nights.
You can pass that number to cm^2 to grasp better the idea of this size:
0.0138 m^2 * (100 cm)^2 / m^2 = 138 cm^2
