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Anuta_ua [19.1K]
3 years ago
14

Construct a position-time graph that shows the forward progress of Sunny The Dog in a straight line for 20 meters over the cours

e of 4 seconds.

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

The answer to your question is the second graph (the one attached).

Explanation:

We have to look for the graph that represents the data given.

a) The first graph is not correct because we look for a distance of 20 m, and this graph only goes from 0 to 10 m.

b) this graph is correct because it covers the distance (20 m) and the time (4 s)

c) This graph could be the right ooption but it is coming back and we look for a forward progress, then this graph is incorrect.

d) This graph shows that the dog is not moving, so this option is wrong.

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Using the following equation, find in seconds 145m = 9 m/s x t-35m
Zina [86]

Answer:

t = 20 s

Explanation:

145 m = 9 m/s × t – 35m

We can obtain the value of t in seconds by doing the following:

145 m = 9 m/s × t – 35m

Add 35 m to both side as shown below:

145 m + 35 m = 9 m/s × t – 35m + 35 m

180 m = 9 m/s × t

Divide both side by 9 m/s

t = 180 m / 9 m/s

t = 20 s

Therefore, the value of t is 20 seconds.

5 0
3 years ago
A 310-g air track cart is traveling at 1.25 m/s and a 260-g cart traveling in the opposite direction at 1.33 m/s. What is the sp
UNO [17]

Answer:

v_{CM}=0.0732\ m/s

Explanation:

given,

mass of the cart 1, m₁ = 310 g

speed of car 1 , v₁ = 1.25 m/s

mass of cart 2, m₂ = 260 g

speed of cart 2, v₂ = -1.33 m/s

speed of center of mass

v_{CM}=\dfrac{m_1v_1 + m_2 v_2}{m_1 + m_2}

v_{CM}=\dfrac{0.31\times 1.25 +0.26\times (-1.33)}{0.31+0.26}

v_{CM}=\dfrac{0.0417}{0.57}

v_{CM}=0.0732\ m/s

Hence, speed of center of mass of the system is equal to 0.0732 m/s

7 0
4 years ago
if a free falling rock were equipped with a speedometer, by how much would it's speed readings increase with each second IF it w
Kaylis [27]
Accelleration(a) is changing of velocity in second.
free fall a = g
speed increase = a = g = 20 (m/s) / s
7 0
3 years ago
How do you find the speed of a hraph
Dmitriy789 [7]

Answer:

If an object moves along a straight line, the distance traveled can be represented by a distance-time graph. In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving.

Explanation:

7 0
3 years ago
The light rays in the illustration below do not properly focus at the focal point. this problem occurs with?
tankabanditka [31]

Answer:

The problem occurs with all spherical mirrors.

Spherical mirrors are practical up to about inches in diameter.

Reflecting telescopes use spherical mirrors for apertures up to about 4 ".

Larger aperture telescopes use parabolic mirrors to obtain sharp focus.

7 0
3 years ago
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