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Anuta_ua [19.1K]
3 years ago
14

Construct a position-time graph that shows the forward progress of Sunny The Dog in a straight line for 20 meters over the cours

e of 4 seconds.

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

The answer to your question is the second graph (the one attached).

Explanation:

We have to look for the graph that represents the data given.

a) The first graph is not correct because we look for a distance of 20 m, and this graph only goes from 0 to 10 m.

b) this graph is correct because it covers the distance (20 m) and the time (4 s)

c) This graph could be the right ooption but it is coming back and we look for a forward progress, then this graph is incorrect.

d) This graph shows that the dog is not moving, so this option is wrong.

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Explanation:

Work is the dot product of the force and displacement vectors.

W = F · d

In other words, it is the force times the parallel component of the distance.

W = F d cos θ, where θ is the angle between the force and distance.

3 0
3 years ago
Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o
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Answer:

\theta = 15^o \: or\: 75^o

Explanation:

As we know that the formula of range is given as

R = \frac{v^2sin2\theta}{g}

now we know that

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now we need to find such angles for which the range is half the maximum value

so we will have

\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}

sin(2\theta) = \frac{1}{2}

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While escaping from a building in which a fire is burning, 40 people pass through a smoky
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8 0
3 years ago
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a = 7.8 m/s^2

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vichka [17]

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3 years ago
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