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antiseptic1488 [7]
3 years ago
8

Positional and non positional different between​

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Explanation:

In positional number system,

1. each symbol represents different value depending on the position they occupy in a number.

2. In positional number system, each system has a value that relates to the number directly next to it. The total value of a positional number is the total of the resultant value of all positions.

3. Example: 12 can be 1 x 10 + 2 x 1, 10 + 2= 12

whereas in Non-Positional number

1. In non-positional number system, each symbol represents the same value regardless of its position

2. In non-positional number system each symbol represents a number with its own place value.

3. Example: Roman number system where I for 1, II for 2 etc.

~~

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Why is acceleration of an object moving at a constant velocity always zero?
k0ka [10]

Answer:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Explanation:

In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

8 0
2 years ago
How much work is needed to pump all the water out of a cylindrical tank with a height of 10 m and a radius of 5 m
balu736 [363]

Answer:

Explanation:

volume of water being lifted

= π r² h , where r is radius of cylinder and h is height of cylinder

= 3.14 x5² x 10

= 785 m³

mass of water = 785 x 10³ kg

mass of this much of water is lifted so that its centre of mass is lifted by height

10 / 2 = 5m .

So work done = mgh , m is mass of water , h is displacement of centre of mass and g is acceleration due to gravity

= 785 x 10³ x 9.8 x 5

= 38.465 x 10⁶ J  

6 0
3 years ago
julia throws a ball vertically upward from the ground with a speed of 5.89m/s. Andrew catches it when it is on its way down at a
aliya0001 [1]
Vo = 5.89 m/s Y = 1.27 m g = 9.81 m/s^2 
Time to height 
Tr = Vo / g Tr = (5.89 m/s) / (9.81 m/s^2) Tr = 0.60 s 
Max height achieved is:
H = Vo^2 / [2g] H = (5.89 )^2 / [ 2 * (9.81) ] H = (34.69) / [19.62] H = 1.77 m 
It falls that distance, minus Andrew's catch distance:
h = H - Y h = (1.77 m) - (1.27 m) h = 0.5 m 
Time to descend is therefore:
Tf = √ { [2h] / g ] Tf = √ { [ 2 * (0.5 m) ] / (9.81 m/s^2) } Tf = √ { [ 1.0 m ] / (9.81 m/s^2) } Tf = √ { 0.102 s^2 } Tf = 0.32 s 
Total time is rise plus fall therefore:
Tt = Tr + Tf Tt = (0.60 s) + (0.32 s) Tt = 0.92 s           (ANSWER)
8 0
3 years ago
Derive this please as fast as u can​
GREYUIT [131]

Answer:

Derived in explanation

Explanation:

The law of universal gravitation was discovered by Newton in 1686. According to this law:

“Every object in this universe attracts other body with a force, which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.”

Consider two bodies ‘A’ and ‘B’ having masses ‘m1’ and ‘m2’, respectively. They are placed with their centers at distance ‘r’ from each other.  

According to this law, force is directly proportional to the product of their masses, that is:

F\ \alpha\ (m_1)(m_2)

Also, the force is inversely proportional to the square of the distance between them, that is:

F\ \alpha\ \frac{1}{r^2}

On combining both equations we get:

Where ‘G’ is called ‘Gravitational Constant’ and its value is 6.67 x 10⁻¹¹ Nm²/kg².

6 0
3 years ago
A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 4 th bounce is meas
goldfiish [28.3K]

Answer:

0.912

Explanation:

Given that

Height of bouncing of the ball, h = 1.71 m

Number of times the ball bounced, n = 4 times

Height from which the ball was dropped, H = 2.47

First, let's start by defining what coefficient of restitution means

Coefficient of Restitution, CoR is the "ratio of the final to initial relative velocity between two objects after they collide. It normally ranges from 0 to 1 where 1 would be a perfectly elastic collision."

It is mathematically represented as

CoR = (velocity after collision) / (velocity before collision)

1.71 = 2.47 * c^4, where c = CoR

1.71/2.47 = c^4

c^4 = 0.6923

c = 4th root of 0.6923

c = 0.912

6 0
3 years ago
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