1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
3 years ago
5

What is the formula for finding diameter from circumference

Mathematics
1 answer:
leva [86]3 years ago
4 0
The equation for the circumference is 2*pi*radius
if you are given the circumference then divide both sides by pi
that is because the diameter is 2 times the radius
so you can rearrange the equation to
C = pi * 2 * r
C = pi * d
divide both sides by pi
C/pi = d

Hope this helps :)
You might be interested in
Help me please (#20) I need this by tomorrow
Rama09 [41]

Answer:

the third one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A = bh/2 solve for b
rjkz [21]
A =  \dfrac{bh}{2}

Cross multiply:
2A = bh

Divide by h on both sides:
b =  \dfrac{2A}{h}
8 0
3 years ago
8th grade math help please (will give brainliest and thanks)
kari74 [83]
Pythagorean Theorem
Height = 3
Length = 5
Hypotenuse^2 = 3^3 + 5^2
Hypotenuse^2 = 9 + 25
Hypotenuse^2 = 34
Line CD = sq root(34) = <span> <span> <span> 5.8309518948 </span> </span> </span>

7 0
3 years ago
Read 2 more answers
What is the surface area of a cube that has 2 inch sides?​
timofeeve [1]

Answer:

A=24in²

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
Other questions:
  • Evaluate the expresion<br> 27+6x2+3/6
    6·1 answer
  • Rita charged $126 for a DVD player at an interest rate of 15.9%. How much will Rita have to pay after 2 months if she makes no p
    13·1 answer
  • The density of copper is 9.86 g/cm3.
    8·2 answers
  • A bag contains
    13·1 answer
  • 1. An airplane flies with a constant speed of 600 km/h. How far can it travel in 3 1/2 hours?
    7·2 answers
  • A student paid 256.37 in school fees how much has he paid to the nearest hundred <br><br>​
    9·2 answers
  • Alvin's age is two times Elga's age. The sum of their ages is 69. What is Elga's age?
    12·2 answers
  • 5. a) A wire has a total length of 8184cm. It was cut into various pieces to form a series of 10 squares. The а length of each s
    6·1 answer
  • Edwin built a picture frame 13 inches long and 10 inches wide out of wood that is 2 inches wide.
    5·2 answers
  • Please answer, Thank you. Image below.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!