Given that,
Deacelectration = -15 m/s²
Negative sign shows the declaration
Slowly speed = 25 m/s
Acceleration = 35 m/s²
Speed = 170 m/s
We need to calculate the time
Using equation of motion
Where, v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the formula
We need to calculate the distance from the original runway
Using equation of motion
Hence, The distance from the original runway is 48.2 m.
I'll just find out the path difference between the waves at the starting point. At infinity, the path difference will be zero because the observer will be infinitely far away from both. As the observer goes farther, the path difference keeps reducing till it reaches zero as the observer reaches infinity.
<span>Path difference at starting point = Distance from lower speaker - Distance from upper speaker = √((3)² + (2.5)²) - 2.5 = 1.405 m </span>
<span>Now to find wavelength. </span>
<span>Speed of sound in air at 20 degrees C = 343 m/s </span>
<span>Wavelength = 343 / 686 = 0.5 m </span>
<span>Destructive interference occurs when path difference = (2n + 1)λ/2 where n is an integer. </span>
<span>Maximum n possible can be found by, </span>
<span>(2n + 1)λ/2 < 1.405 </span>
<span>(2n + 1) < (1.4)(2) / (0.5) </span>
<span>2n < 5.6 - 1 </span>
<span>2n < 4.6 </span>
<span>n < 2.3 </span>
<span>So, we have 3 values of n, 0, 1 and 2. </span>
<span>Path differences are, λ/2, 3λ/2 and 5λ/2 which have values 0.25 m , 0.75 m and 1.25 m </span>
<span>But the question asks for distance from starting point. (sheesh!!) </span>
<span>Lets say the observer walked x distance. </span>
<span>Path difference = √((3)² + (2.5 + x)²) - (2.5 + x) </span>
<span>Equate this expression to the values obtained above to get the different values of x. </span>
Answer:
Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.
B = magnetic field in the cyclotron = 0.400 T
q = magnitude of charge on a proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷ kg
f = frequency of revolution of proton in the cyclotron = ?
v = speed of electromagnetic waves = 3 x 10⁸ m/s
λ = wavelength of electromagnetic wave = ?
Frequency of revolution of proton in the cyclotron is given as
f = qB/(2πm)
inserting the values
f = (1.6 x 10⁻¹⁹)(0.400)/(2 (3.14) (1.67 x 10⁻²⁷))
f = 6.1 x 10⁶ Hz
wavelength of electromagnetic wave is given as
λ = v/f
λ = (3 x 10⁸)/(6.1 x 10⁶)
λ = 49.2 m
