Answer:
8) 1500 feet
9) 20 miles
10) 4 Days
11) 2250 miles
12) 1 hour and 5 minutes
13) 27.27miles per hour
Explanation
8) There are 60 seconds in one minute so 60x25=1500 feet
9) 30 minutes is half of an hour so 40 miles ÷ 2 = 20 miles
10) 12x4=48
11) 500 miles x 4.5 hours is 2250 miles
12) Train leaves at 3pm after 60 miles it will be 4 pm and after 5 more miles 4:05 pm so 1 hour and 5 minutes
13)
Elmo = 40 minutes and 5 miles
Bert and Ernie = 45 minutes and 15 miles
Cookie Monster = 20 minutes and 10 miles
Home = 5 minutes abd 20 miles
Average Speed including stops is 27.27 miles per hour
Answer:
The rate at which velocity changes with respect to a change in time is called. acceleration.
Explanation:
<em>Answer:</em>
<h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>True</em></h3>
- <em>Because </em><em>Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.</em>
<em>Carryonlearning</em>
Question:
A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?
Answer:
Time for the race will be t = 9.26 s
Explanation:
Given data:
As the sprinter starts the race so initial velocity = v₁ = 0
Distance = s₁ = 20 m
Acceleration = a = 4.20 ms⁻²
Distance = s₂ = 100 m
We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.
Using 3rd equation of motion
(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)
v₂ = 12.96 ms⁻¹
Time for 20 m distance = t₁ = (v₂ - v ₁)/a
t₁ = 12.96/4.2 = 3.09 s
He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be
Time for 100 m distance = t₂ = s₂/v₂
t₂ = 80/12.96 = 6.17 s
Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s
T = 9.26 s
My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height.
Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
<h3>How does tension affect the speed of a wave in a rope?</h3>
The Increase of the tension placed on a string is one that tends to increases the speed of a wave, which in turn also increases the frequency of any given length.
Therefore, My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height. Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
Learn more about tension from
brainly.com/question/2008782
#SPJ4
See full question below
(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.
