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kari74 [83]
3 years ago
9

Hold a pencil in front of your eye at a position where its blunt end just blocks out the Moon. Make appropriate measurements to

estimate the diameter of the Moon, given that the Earth–Moon distance is 3.8 × 105 km. Assume that the pencil has a diameter of about 0.7 cm, and it just blocks out the Moon if it is held about 0.75 m from the eye.Express your answer using two significant figures.
Physics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

D = 3.6 \times 10^6 m

Explanation:

Since the diameter of the moon position and the diameter of pencil position are in same line

so the angle made by the rays coming from the sun will be same as the angle made by the pencil lead at eye position

so we will have

\frac{D}{L} = \frac{d}{x}

here we have

D = diameter of moon

d = diameter of pencil lead = 0.7 cm

L = 3.8 \times 10^8 m

x = 0.75 m

so we have

\frac{0.007}{0.75} = \frac{D}{3.8 \times 10^8}

D = 3.6 \times 10^6 m

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Answer:

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the specific volumes are:

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final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

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What is the wavelength of a wave if its frequency is 256 Hz and speed of the wave is 350 m/s?
DiKsa [7]

Answer:

Explanation:

The equation for this is

f=\frac{v}{\lambda} where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:

256=\frac{350}{\lambda} and

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Assuming 84.0% efficiency for the conversion of electrical power by the motor, what current must the 13.0-V batteries of a 716 k
tino4ka555 [31]

Answer:

\mathbf{ current(I) =1766.67 \ A}

Explanation:

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