Let's assume that the number we are using is
![a+bi](https://tex.z-dn.net/?f=a%2Bbi)
, where
![a](https://tex.z-dn.net/?f=a)
and
![b](https://tex.z-dn.net/?f=b)
are real numbers. The conjugate of this would be
![a-bi](https://tex.z-dn.net/?f=a-bi)
. Multiplying the two together would get
![(a+bi)*(a-bi)= a^{2} + abi - abi + b^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=%28a%2Bbi%29%2A%28a-bi%29%3D%20a%5E%7B2%7D%20%2B%20abi%20-%20abi%20%2B%20b%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D%20)
. Since
![a](https://tex.z-dn.net/?f=a)
and
![b](https://tex.z-dn.net/?f=b)
are both real numbers, the multiplication of the conjugate must also be real.
Answer:
4
Step-by-step explanation:
if 1/4 = 3/12 then 3/12+ 3/12+ 3/12+ 3/12
i hope i did this right
Answer:
b. ![x\approx -2.426](https://tex.z-dn.net/?f=x%5Capprox%20-2.426)
Step-by-step explanation:
The given equation is;
![x^3+x^2+10x+15=0](https://tex.z-dn.net/?f=x%5E3%2Bx%5E2%2B10x%2B15%3D0)
We solve by the x-intercept method. We need to graph the corresponding function using a graphing tool.
The corresponding function is
![f(x)=x^3+x^2+10x+15](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3%2Bx%5E2%2B10x%2B15)
The solution to
is where the graph touches the x-axis.
We can see from the graph that; the x-intercept is;
(-2.426,0)
Therefore the real solution is:
![x\approx -2.426](https://tex.z-dn.net/?f=x%5Capprox%20-2.426)
Answer:
1. 1/7
2. 1/5
3. 5/7
4. 5/6
5. 1/3
6. 2/5
7. 2/3
8. 3/7
9. 1/10
10. 4/7
Step-by-step explanation:
Hope this helps!
Answer:
about a year I think
Step-by-step explanation: