<span>Friction creates heat which in turn can lead to deviations from the original size and shape of a part.
</span>
Boyle Law says “the pressure of fixed amount of ideal gas which is at constant temperature is
inversely proportional to its volume".<span>
P = 1/V
<span>Where, P is pressure of the ideal gas and V is volume of the ideal gas.</span>
<span>For two situations, this law can be added as;
P</span>₁V₁ = P₂V₂<span>
</span><span>14 lb/in² x V₁ = 70 lb/in² x 500 mL</span><span>
</span><span>V₁ =
2500 mL</span><span>
Hence, the needed volume of atmospheric air = 2500
mL
<span>Here, we made two </span>assumptions. They are,
1. The
atmospheric air acts as ideal gas.
2.
Temperature is a constant.
<span>We didn't convert the units to SI units since
converting volume and pressure are products of two numbers, they will cut off. </span></span></span>
Answer:
The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.
Explanation:
Distillation is a type of the separation process by physical means of a mixture on basis of its difference in boiling point or vapor pressure .
Where we can just heat the mixture and separate out the components i.e the component with lower boiling point will form vapor easily and can be later condensed whereas the component with higher boiling point will remain as residue.
In case of a distillation column the same principle is applied at different stages to separate multiple components .The stages are known as trays or plates . In general , there is a certain liquid on each of the plate, and the arrangements are made for the ascending vapors to pass through the liquid and make contact with it . The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.
Answer:
Explanation:
Molal freezing point depression constant of butanol Kf = 8.37⁰C /m
ΔTf = Kf x m , m is no of moles of solute per kg of solvent .
mol weight of butanol = 70 g
235.1 g of butanol = 235.1 / 70 = 3.3585 moles
3.3585 moles of butanol dissolved in 4.14 kg of water .
ΔTf = 8.37 x 3.3585 / 4.14
= 6.79⁰C
Depression in freezing point = 6.79
freezing point of solution = - 6.79⁰C .
Answer:
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