All categories

3 years ago

While camping you light a small campfire, initiating the combustion of wood to produce heat and

Chemistry

1 answer:

Ksju [112]3 years ago

5 0

Answer:

A. It is exothermic

Explanation:

Combustion is a chemical reaction in which a substance combines with oxygen present in air to produce carbon (iv) oxide and water as well release heat and light energy.Combustion is an exothermic process.

An exothermic reaction releases energy in the form of heat to the surroundings. The energy required to break bonds in the reactants is less than the energy required to form new bonds in the products in an exothermic reaction.

From the given options;

A. It is exothermic is determinable since the reaction is a combustion reaction

B. The bond making energy is more than 600 kJ is not certain because the mass of the wood being burnt is not given. Also, wood is not composed of a specific element that would be taking part in the reaction, rather it is composed of various substances.

C. It is endothermic. is wrong because combustion of wood is exothermic.

D. The bond breaking energy is more than 600 kJ is not certain because the mass of the wood being burnt is not given. Also, wood is not composed of a specific element that would be taking part in the reaction, rather is composed of many substances.

You might be interested in

WILL GIVE BRAINLIEST Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.

Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

Structure of H2S :

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) 3s(2 )3p(4)

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these 6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4 are non- bonding and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

Structure of H2S :

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.

Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S shifts way from lone pair

5 0

3 years ago

Choose the correct missing coefficient to balance the following equation:

ira [324]

Answer:

the answer is 2 hope this helps

6 0

2 years ago

If a snack cake contains 450 food calories and Carla

Oksana_A [137]

Answer:

9/10hr

Explanation:

From the question given:

Carla was able to burn 250 calories by running for one-half (1/2)hr.

Therefore, Carla will burn 450calories by running for = (450x1/2) /250 = 225/250 = 9/10hr

8 0

3 years ago

What is atomic radius? Does it decrease going up or down a group?

shusha [124]

The atomic radius increases as you go down a group.

5 0

3 years ago

List the symbols for all the elements with electron configurations that end as follows. Each n represents an energy level.

Gwar [14]

List the symbols for all the elements with electron configurations that end as follows. Each n represents an energy level.

a. ns1

b. ns2np4

Answer: a) H, Li, Na, K, Rb, Cs, and Fr

b) O, S, Se, Te, Po

Explanation:

a. Determining the elements correlating to the electron configuration of "ns1" , you should understand that this suggests that the elements are in Group 1A.

This is because that there is one electron in an s-orbital. The orbital is located in the first column of the periodic table.

Thus, the elements that have this electron configuration are H, Li, Na, K, Rb, Cs, and Fr.

b. Determining the elements correlating to the electron configuration of ns^2np^4 characterizes group 6A of the periodic table.

This is because that there is have six valence electrons in their highest-energy orbitals (ns2np4). The orbital is located in the first column of the periodic table.

Thus, the elements that have this electron configuration are the nonmetals oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po).

6 0

3 years ago