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VikaD [51]
4 years ago
10

Consider the gas-phase reaction, 2 so2 + o2 <=> 2 so3, for which kp = 2 at a given temperature. If the mixture is analyzed

and found to contain 2.2 bar of so2, 1.6 bar of o2 and 3.4 bar of so3, describe the situation:
Chemistry
1 answer:
Digiron [165]4 years ago
8 0

The given reaction is

                    2 SO2 + O2 <=> 2 SO3, for which kp = 2 at a given temperature

Equilibrium constant = pSO3^2 / pSO2^2 X pO2

Q= (3.4)^2 / (2.2)^2 X 1.6 = 1.5

As Q< Kp

The reaction is not at equilibrium and reaction will go in forward direction

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Enthalpy of combustion of ethyl alcohol, C2 H5 OH, is – 950 kJ mol–1. How much heat is evolved when one gram of ethyl alcohol bu
melomori [17]
<h3>Answer:</h3>

20.62 Kilo-joules

<h3>Explanation:</h3>
  • The Enthalpy of combustion of ethyl alcohol is -950 kJ/mol.
  • This means that 1 mole of ethyl alcohol evolves a quantity of heat of 950 Joules when burned.

Molar mass of ethyl ethanol = 46.08 g/mol

Therefore;

46.08 g of  C₂H₅OH evolves heat equivalent to 950 kilojoules

We can calculate the amount of heat evolved by 1 g of C₂H₅OH

Heat evolved by 1 g of C₂H₅OH  = Molar enthalpy of combustion ÷ Molar mass

                                      = 950 kJ/mol ÷ 46.08 g/mol

                                      = 20.62 Kj/g

Therefore, a gram of C₂H₅OH  will evolve 20.62 kilo-joules of heat

7 0
3 years ago
Which alkaline earth metal has the highest ionization energy? Refer to the periodic table.
Liula [17]
I’m pretty sure the answer is Barium. I hope it helps.
4 0
3 years ago
Read 2 more answers
The hot dogs you ate at the barbecue last week were 75% fat-free by weight, had 275 calories, and weighed 110 g. a) What percent
vovangra [49]

Answer:

a) 25%

b) 27.5 g

c) 90%

Explanation:

a) 75% fat-free by weight means 25% of the weight is made by fat.

b) 110 g ___ 100%

      x    ___ 25%

          x = 27.5g

Each hot dog has 27.5g of fat.

c) 9 cal ___ 1 g fat

      y    ___ 27.5 g fat

          y = 247.5 cal

275 cal ___ 100%

247.5 cal ___ z

     z = 90%

90 % of the calories come from fat.

6 0
3 years ago
How many molecules are in 0.79 moles of NH4?
erik [133]

Answer:

14

Explanation:

5 0
3 years ago
How are the following aspects of a reaction affected by the addition of a catalyst? 1) activation energy of the reverse reaction
snow_tiger [21]

These are four questions and four answers.

Answers:

1) activation energy of the reverse reaction

     b. Decreased

2) Rate of the forward reaction

    a. Increased

3) Rate of the reverse reaction

    a. Increased

4) Activation energy of the forward reaction

    b. decreased

Explanation:

<em>Activarion energy</em> is the energy required by the reactants to form the intermediate transition state and become products.

<em>Catalysts</em> are substances that change the path of the chemical reactions, lowering the activation energy, and thus speeding up the rate of the reactions, since the products can reach the new lower activation energy faster.

The equilibrium reactions are the chemical process in which two reactions, the <em>forward and the reverese reactions</em>, occur simultaneously and at the same rate.  The equlibrium reactions may be represented by:

  • A ⇄ B

Where A → B is the direct or forward reaction, and A ← B is the reverse reaction (note the inversed arrow, from right to left).

For the direct reaction A represents the reactants and B represents the products. On the other hand, B represents the reactants and A represents the reactants of the reverse reaction and A. This, is A is the reactant of the forward reaction and the product of the reverse reaction, while B is the reactant of the reverse reaction and the product of the forward reaction.

Since, <em>the addition of a catalyst</em> lowers the activation energy of the process, the new activation energy is lower for both the forward and the reverse reaction, meaning that:

1. <em>The activation energy of the reverse reaction is decreased</em> (option b. of the first question)

2.<em> The rate of the forward reaction is increased</em> (option a. of the second question)

3. <em>The rate of the reverse reaction is increased</em> (option a. of the third question).

4. <em>Activation energy of the forward reaction is decreased</em> (option b. of the fourth question).

In summary, the addition of a catalyst decreases the activation energy for both forward and reverse reactions, and increases the rate of both forward and reverse reactions.

3 0
3 years ago
Read 2 more answers
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