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uranmaximum [27]
4 years ago
8

Find the lesser of two consecutive integers with a sum greater than 16.

Mathematics
2 answers:
Cerrena [4.2K]4 years ago
8 0
A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
klasskru [66]4 years ago
4 0

Answer:  The required lesser integer is 8.

Step-by-step explanation:  We are given to find the lesser of two consecutive integers with a sum greater than 16.

Let n and (n + 1) be the two consecutive integers.

Then, according to the given information, we have

n+(n+1)>16\\\\\Rightarrow 2x+1>16\\\\\Rightarrow 2n>16-1\\\\\Rightarrow 2n>15\\\\\Rightarrow n>\dfrac{15}{2}\\\\\Rightarrow n>7.5.

Thus, the required lesser integer is 8.

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now we do the same only different way ok

48x-6y=16

Divide both sides of the equation by 2

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