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uranmaximum [27]
3 years ago
8

Find the lesser of two consecutive integers with a sum greater than 16.

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
klasskru [66]3 years ago
4 0

Answer:  The required lesser integer is 8.

Step-by-step explanation:  We are given to find the lesser of two consecutive integers with a sum greater than 16.

Let n and (n + 1) be the two consecutive integers.

Then, according to the given information, we have

n+(n+1)>16\\\\\Rightarrow 2x+1>16\\\\\Rightarrow 2n>16-1\\\\\Rightarrow 2n>15\\\\\Rightarrow n>\dfrac{15}{2}\\\\\Rightarrow n>7.5.

Thus, the required lesser integer is 8.

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lawyer [7]

The 5 number summary are

Minimum = 10, Lower quartile = 11, Median = 12, Upper quartile = 17 and Maximum = 19

<h3>How to identify the 5 number summary?</h3>

The complete question is in the attached image

The 5 number summary of box plot are:

  • Minimum
  • Lower quartile
  • Median
  • Upper quartile
  • Maximum

Each of these summaries are represented by the vertical lines of the box plot

From the attached box plot, we have:

Minimum = 10, Lower quartile = 11, Median = 12, Upper quartile = 17 and Maximum = 19

Read more about 5 number summary at:

brainly.com/question/12490978

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