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uranmaximum [27]
3 years ago
8

Find the lesser of two consecutive integers with a sum greater than 16.

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
klasskru [66]3 years ago
4 0

Answer:  The required lesser integer is 8.

Step-by-step explanation:  We are given to find the lesser of two consecutive integers with a sum greater than 16.

Let n and (n + 1) be the two consecutive integers.

Then, according to the given information, we have

n+(n+1)>16\\\\\Rightarrow 2x+1>16\\\\\Rightarrow 2n>16-1\\\\\Rightarrow 2n>15\\\\\Rightarrow n>\dfrac{15}{2}\\\\\Rightarrow n>7.5.

Thus, the required lesser integer is 8.

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Hey you!<br><br> I think I need your help with this one - Thanks~
timofeeve [1]
Hey Gary!

The volume of a cylinder is PiR^2h, or 3.14(r^2)h.
Let's define our measures.
Pi is 3.14 (simplified). However, our answer is requested in terms of Pi.
Our radius is 5.
Our height is 14.
Let's plug in our numbers.

5^2 • 14 • Pi
5^2 = 25
25 • 14 = 350.

350Pi is our answer.
However, rememver that we need to end our answer in units cubed, as we are using a 3-dimensional figure. Our answer is 350Pi in^3.
Your answer is B.)

I hope this helps!



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