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uranmaximum [27]
3 years ago
8

Find the lesser of two consecutive integers with a sum greater than 16.

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
klasskru [66]3 years ago
4 0

Answer:  The required lesser integer is 8.

Step-by-step explanation:  We are given to find the lesser of two consecutive integers with a sum greater than 16.

Let n and (n + 1) be the two consecutive integers.

Then, according to the given information, we have

n+(n+1)>16\\\\\Rightarrow 2x+1>16\\\\\Rightarrow 2n>16-1\\\\\Rightarrow 2n>15\\\\\Rightarrow n>\dfrac{15}{2}\\\\\Rightarrow n>7.5.

Thus, the required lesser integer is 8.

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mafiozo [28]
The amount of x is 28

6 0
3 years ago
2. What is the length of<br> side c? Someone help
kirza4 [7]
A*2 + b* = c*2

(9)*2 + (8)*2

81+64= 145

145=c*2
12.04=c
7 0
3 years ago
Read 2 more answers
Solve the equation.<br><br> 5d = 17.1<br><br><br> 12.1<br><br> 22.1<br><br> 85.5<br><br> 3.42
Rudiy27

Hello there!


5d = 17.1

The equation is asking you to find the value for "d". How to do that? Well, all you have to do is divide both side by 5.

5d/5 = 17.1

d = 3.42  

That's your answer!


You can even double check your work, if you want to. How? Well, you just need to replace 3.42 where it belongs.

5(3.42) = 17.1

17.1 = 17.1

True!


Let me know if you have additional questions. As always, it is my pleasure to help students like you!

7 0
3 years ago
Read 2 more answers
100 POINTS FOR WHOEVER ANSWER THIS QUESTION FULLY!!!
natulia [17]

Answer:

  • Yes, diagonals bisect each other

Step-by-step explanation:

<em>See attached</em>

Plot the points on the coordinate plane

Visually, it is seen that the diagonals bisect each other.

We can prove this by calculating midpoints of AC and BD

<u>Midpoint of AC has coordinates of:</u>

  • x = (1 - 1)/2 = 0
  • y = (4 - 4)/2 = 0

<u>Midpoint of BD has coordinates of:</u>

  • x = (4 - 4)/2 = 0
  • y = (-1 + 1)/2 = 0

As per calculations the origin is the bisector of the diagonals.

7 0
3 years ago
Find the radius of a circle, given that the center is at (3,-3) and the point (7,6) lies on the circle.
Alenkasestr [34]

Answer:

\large\boxed{radius=\sqrt{97}}

Step-by-step explanation:

The radius is the distance between the center and any point on the circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the center (3, -3) and other point on the circle (7, 6).

Substitute:

r=\sqrt{(6-(-3))^2+(7-3)^2}=\sqrt{9^2+4^2}=\sqrt{81+16}=\sqrt{97}

3 0
3 years ago
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