Answer:
see graph
Step-by-step explanation:
g(x) = 3^ x .
h(x) = 2^-x
We want to subtract them
f(x) = 3^x - 2^(-x)
I will rewrite without the negative exponent
f(x) = 3^x - (1/2)^(x)
Lets pick a couple of points
f(0) = 3^0 - (1/2) ^ 0 = 1-1 = 0
As x gets large 3^x gets large and 1/2^x gets close to 0, so it will get large
As x goes to negative infinity, 3^x goes to zero and 1/2^ gets large so we get - infinitity
Answer:
x=-1
Step-by-step explanation:
Treat this as you would the quadratic equation x^2 - 4x - 3 + 0. Solve this by completing the square:
x^2 - 4x + 4 - 4 - 7 = 0
(x^2 - 4x + 4) = 11
(x-2)^2 = 11, and so x-2 = plus or minus sqrt(11).
Graph this, using a dashed curve (not a solid curve). Then shade the coordinate plane ABOVE the graph.
-12 + 9 - (-3) - 11
Remember PEMDAS: This is the order of operation.
P-Paragrahp
E-Exponent
M-Multiply
D-Divide
A-Add
S-Subtract
1st step: PEM
-(-3) is actually -1 * -3 = + 3
-12 + 9 + 3 - 11
2nd step: D is not possible, so we do A.
9 + 3 = 12
3rd Step: Subtract
12 - 12 - 11 = 0 - 11 = -11 CHOICE B.
