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egoroff_w [7]
3 years ago
8

Which of the following reactions will not occur as written? Which of the following reactions will not occur as written? Sn (s) +

2AgNO3 (aq) → 2Ag (s) + Sn(NO3)2 (aq) Zn (s) + Pb(NO3)2 (aq) → Pb (s) + Zn(NO3)2 (aq) Co (s) + 2HI (aq) → H2 (g) + CoI2 (aq) Mg (s) + Ca(OH)2 (aq) → Ca (s) + Mg(OH)2 (aq) Co (s) + 2AgCl (aq) → 2Ag (s) + CoCl2 (aq)
Chemistry
2 answers:
galben [10]3 years ago
6 0

Answer:I have no idea

Explanation:

Why is this so complex…

Sati [7]3 years ago
4 0

Answer: Option (4) is the correct answer.

Explanation:

According to the reactivity series, a more reactive metal has the ability to replace a less reactive metal in a chemical reaction.

It is known that calcium is more reactive than magnesium. So, in a chemical reaction magnesium can never replace calcium.

For example, Mg(s) + Ca(OH)_2(aq) \rightarrow Ca(s) + Mg(OH)_2(aq)

Therefore, this given reaction is not possible. But rest all given reactions are possible.

Thus, we can conclude that out of the given options Mg(s) + Ca(OH)_2(aq) \rightarrow Ca(s) + Mg(OH)_2(aq) reaction will not occur as written.

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Ans with solution...
Licemer1 [7]

Answer:

The answer to your question is:

Vol of NO2 = 11.19 L

Vol of O2 = 2.8 L

Explanation:

Data

N2O5 = 56 g

STP     T = 0°C = 273°K

           P = 1 atm

MW N2O5 = 216 g

Gases law = PV = nRT

Process

                   216 g of N2O5 ---------------- 1 mol

                     54 g               -----------------  x

                    x = (54 x 1) / 216

                    x = 0.25 mol of N2O5

                   2 mol of N2O5 -----------------  4 mol of NO2

                   0.25 mol          ------------------    x

                   x = (0.25 x 4) / 2 = 0.5 mol of NO2

                   V = nRT/P

                   V = (0.5)(0.082)(273) / 1 = 11.19 L

                   2 mol of N2O5 ----------------- 1 O2

                   0.25 N2O5 ----------------------  x

                   x = (0.25 x 1) / 2 = 0.125 mol

                   Vol = (0.125)((0.082)(273) / 1 = 2.8 L

3 0
4 years ago
What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?
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<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. Calculations are as follows:

Molarity of NO3 ion = 32.0 g Mg(NO3)2 ( 1 mol / 148.3 g ) ( 2 mol NO3 / 1 mol Mg(NO3)2) / .425 L
MOlarity of NO3 ion = 1.02 M </span><span>
</span>
8 0
3 years ago
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