1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sholpan [36]
3 years ago
5

What is not a function of stomata in the leaves of a plant (PLEASE ANSWER HURRY)

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0
Answer
B
Explanation
You might be interested in
A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].
Angelina_Jolie [31]

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As,       N_{A} \propto (P_{A1} - P_{A2})

           N_{A} = K_{G} \times (P_{A1} - P_{A2})

Therefore, putting the given values into the above formula as follows.

         N_{A} = K_{G} \times (P_{A1} - P_{A2})

                     = 0.88 \times (0.2 atm - 0.05 atm)

                     = 0.132 mol/h.ft^{2}

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 mol/h.ft^{2}

4 0
4 years ago
What is the name for the process of recycling materials that make up the earths crust and mantle
Step2247 [10]
The answer is the rock cycle
4 0
3 years ago
Read 2 more answers
The molar heat capacity for carbon monoxide at constant volume is CV,m = 20.17 J/(K·mol). A 3.00-L fixed-volume flask contains C
kompoz [17]

ΔS = 0.250 J·K^(-1)

<em>Step 1</em>. Calculate the <em>moles of CO</em>

From the<em> </em><em>Ideal Gas Law</em>,

<em>n</em> = (<em>pV</em>)/(<em>RT</em>) = (8.00 kPa × 3.00 L)/(8.314 kPa·L·K^(-1)·mol^(-1) × 298.15 K)

= <em>0.009 682 mo</em>l  

Δ<em>S</em> = <em>nC</em>_Vln(<em>T</em>_2/<em>T</em>1)

= 0.0096 82 mol × 20.17 J·K^(-1)mol^(-1) ln(1073.15 K/298.15 K)

=  0.1953 J·K^(-1) × ln3.599 = 0.250 J·K^(-1)

5 0
4 years ago
How much energy is required when a 142.1 gram sample of aluminum goes from 25.5°C to 46°C? (the specific heat of aluminum is 0.9
vfiekz [6]

Answer:

2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

Explanation:

Given data:

Mass of sample = 142.1 g

Initial temperature = 25.5°C

Final temperature = 46°C

Specific heat capacity of Al = 0.90 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 46°C - 25.5°C

ΔT = 20.5°C

Q = 142.1 × 0.90 J/g.°C × 20.5°C

Q = 2621.75 j

Thus,  2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

4 0
3 years ago
3.45 x 10^20 molecules of sulfur dioxide to miles of sulfur dioxide
topjm [15]
(3.45 x 10^20 molecules of sulfur dioxide ) x \frac{1 mole sulfur dioxide}{6.022x10^23 molecules sulfur dioxide} = 5.73x10^-4 mole of sulfur dioxide
8 0
4 years ago
Other questions:
  • Which of the following elements has two valence electrons?
    8·2 answers
  • A compound die will be used to blank and punch a large washer out of aluminum alloy sheet stock 3.2 mm thick. the outside diamet
    8·1 answer
  • Attached are two chemistry questions I need help with. thank you to whoever helps me out
    11·1 answer
  • A small rock lies on a slope near a tropical sea. What are three ways that the rock could be eroded?
    10·2 answers
  • Which statement is true for a solution when its concentration of hydroxide ions becomes equal to the concentration of hydronium
    11·2 answers
  • What will cause an object to move?
    7·1 answer
  • If I add wheels to a cart to move it, will it have more or less friction than trying to
    11·1 answer
  • A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K
    9·1 answer
  • decide how to supersets these substances? If if is not possible, please write "cannot be separated" on the space provided​
    6·1 answer
  • The model on the right looks bumpy, but when you break a large salt crystal in two, the edges of the split often look straight a
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!