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3 years ago

Any expert know what is the answer?

Chemistry

1 answer:

cupoosta [38]3 years ago

3 0

Alkanes are non-polar: not soluble in water

alcohol is polar: soluble in water

The polarity of alcohols is affected by the -OH (hydroxyl) group, more OH, more polar, while non-polarity of alcohols is influenced by the carbon chain. the longer the carbon chain, the lower the polarity, the lower the solubility

butane : alkane: not soluble

1-2, ethanediol: alcohol: has 2 OH

Butanol has a longer carbon chain than ethanol

So the order of solubility in water (from largest to smallest)

1-2, ethanediol, ethanol, butanol, butane

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For 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), if you begin with 16.00 g ammonia and excess oxygen, how many grams of water will be ob

iragen [17]

12.7 grams approximately

8 0

4 years ago

Choose all the correct answers.

adoni [48]

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4 0

3 years ago

Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A

Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is $\text{Rate}=k[NO_3][CO]$

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

$NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)$

The intermediate reaction of the mechanism follows:

Step 1: $2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}$

Step 2: $NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[NO_3][CO]$

Hence, the rate law for the reaction is written above.

5 0

4 years ago

The formula equation of Sodium carbonate + hydrochloric acid

dusya [7]

Answer:

the reaction is: Na2CO3 + 2HCl ===》 2NaCl + H2O + CO2(g)

6 0

3 years ago

In sodium chloride, which atom loses an electron?

Fittoniya [83]

Answer:

Option B. Sodium

Explanation:

In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:

Na —> Na+ + e- ....... (1)

Cl + e- —> Cl- ......... (2)

Now, combining equation 1 and 2 we have:

Na + Cl + e- —> Na+ + Cl- + e-

Cancelling the electron from both side, we obtained:

Na + Cl —> Na+Cl-

From the above illustration, we see clearly that sodium loses electron

3 0

3 years ago

Read 2 more answers