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enot [183]
3 years ago
11

A solution of naoh(aq) contains 8.1 g of naoh(s) per 100.0 ml of solution. calculate the ph and the poh of the solution at 25 °c

.
Chemistry
1 answer:
olga2289 [7]3 years ago
3 0
My Brother your answers is: 
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What does the quantum number ml describe?
yawa3891 [41]

Answer:

Magnetic Quantum Number (ml): ml = -l, ..., 0, ..., +l. Specifies the orientation in space of an orbital of a given energy (n) and shape (l). This number divides the subshell into individual orbitals which hold the electrons; there are 2l+1 orbitals in each subshell.

8 0
2 years ago
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16.0 grams of oxygen gas reacted with 80.0 grams nitrogen monoxide gas producing 25.0 grams of nitrogen dioxide gas in the lab.
Anon25 [30]

Answer:

Limiting reactant  = O₂

Excess reactant = NO

Theoretical yield of NO₂ = 46 g

Mass of excess reactant = 30 g

<h3 />

Explanation:

O₂ + 2NO → 2NO₂

Mole ratio for the reaction is;

1 : 2 → 2

mass of O₂ = 16 g

mass of NO = 80 g

mass of NO₂ = 25 g

molecular weight  of O₂ = 32 g/mol

molecular weight  of NO = 30 g/mol

molecular weight  of NO₂ = 46 g/mol

molar mass of O₂ = mass ÷ molecular weight = 16 g ÷ 32 g/mol = 0.5 mol

molar mass of NO = mass ÷ molecular weight = 80 g ÷ 30 g/mol = 2.67 mol

Since, 1 mole of O₂ requires 2 moles of NO for the combustion reaction, 0.5 mole shall require 1 mole of NO for the reaction. Thus, O₂ is the limiting reactant and NO is the excess reactant as it has an excess of 2.67 mol - 1 mol = 1.67 mol.

<h3>Theoretical yield of NO₂</h3><h3 />

1 mole of O₂ shall yield 2 moles of NO₂

Thus, 0.5 mole of O₂ shall yield 1 mole of NO₂

mass of NO₂ = molecular weight * molar mass = 46 g/mol * 1 mole = 46 g

<h3>Mass of Excess Reactant</h3>

1 mole of O₂ shall react with 2 moles of NO

Thus, 0.5 mole of O₂ shall yield 1 mole of NO

mass of NO = molecular weight * molar mass = 30 g/mol * 1 mole = 30 g

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How many moles of water (H2O) are present in a beaker containing 45.9 g H2O? Give your answer to the correct number of significa
charle [14.2K]

Explanation:

Number of moles is defined as the mass of given sample divided by the molar  mass of sample.

Mathematically,      No. of moles = \frac{mass given}{Molar mass}

Since, it is given that mass of water is 45.9 g and it is known that molar mass of water is 18.02 g/mol.

Therefore, calculate the number of moles as follows.

               No. of moles = \frac{mass given}{Molar mass}

                                     = \frac{45.9 g}{18.02 g/mol}

                                     = 2.547 mol

Thus, we can conclude that there are 2.547 mol present in 45.9 g of water.

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