Answer:
A: Estuaries provide a nursery grounds for oceanic organisms
Explanation:
the estuaries provide Ov2 and HvO2 for these organism
Answer:
pH ( potential Hydrogen ) is a negative logarithm of molar concentration of hydrogen ions.
therefore:
Answer:
Time of vaporization = 0.588 minutes
Explanation:
The latent heat of fusion is the heat required to change the substance from solid (ice) to liquid completely, without further increase in temperature.
The latent heat of vaporization is the heat required to change a liquid to gas completely, without an increase in temperature.
Latent heat of vaporization = 6.8 times Latent heat of fusion
This means that the time it takes for the latent heat of vaporization to complete vaporization is 6.8 times lesser than the time it takes for the latent heat of fusion to complete fusion
Time of vaporization = 6.8 times lesser than time of fusion
Time of vaporization = (time of fusion) ÷ 6.8
where: Time of fusion = 4 minutes
∴ Time of vaporization = 4 ÷ 6.8
Time of vaporization = 0.588 minutes
This is a combined gas law problem, according to which
where P is the pressure of the gas, V is the volume of the gas, and T is the temperature of the gas, and the subscripts 1 and 2 correspond to the initial and final conditions of the gas. In this problem, we are given the initial pressure, volume, and temperature of the gas in the balloon:
P₁ = 1.0 atm
V₁ = 1.8 L
T₁ = 295.15 K (K = °C + 273.15).
Moreover, we are given the final pressure and temperature of the gas in the balloon.
P₂ = 0.86 atm
T₂ = 281.15 K.
What we want to find is the final volume, V₂, which we can obtain by rearranging the combined gas equation to solve for V₂:
This answer has three significant figures. However, the question as written would warrant an answer that comprises one significant figure (as 8 °C has only one sig fig). In that case, the answer would be 2 L. If the answer is to be given to two significant figures, the volume would then be 2.0 L.
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because. it is the rate-limiting step
<h3>What is
phosphorylation?</h3>
The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar. In the first phase of glycolysis, D-glucose is converted to D-glucose-6-phosphate using the chemical equation D-glucose + ATP D-glucose-6-phosphate + ADP G° = 16.7 kJ/mol (° signifies measurement under standard conditions).
The rate-limiting stage in the liver's metabolism of glucose is the initial rate of phosphorylation of glucose (ATP-D-glucose 6-phosphotransferase) and non-specific hexokinase. Hepatic cells are freely permeable to glucose (ATP-D-hexose 6-phosphotransferase).
encouraging certain glucose transporters to translocate to the cell membrane.
To learn more about phosphorylation from the given link:
brainly.com/question/2138188
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