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11Alexandr11 [23.1K]
3 years ago
5

John performs an experiment on an electric circuit. He increases the voltage from 25 volts to 50 volts while keeping the resista

nce constant. What will be the effect of John’s changes on the current?
The current will increase.

The current will decrease.

The current will stay constant.

The current will stop flowing.
Physics
2 answers:
RSB [31]3 years ago
7 0
According to the Ohm's law, We know, potential difference(v) is directly proportional to electric current (I):

So, as voltage is increased by double of it's initial value, Current will also increase to it's double amount.

In short, Your Correct Answer would be option A) The Current Will Increase

Hope this helps!
Anna71 [15]3 years ago
3 0

Answer:

The current will increase.

Explanation:

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Answer:

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Explanation:

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2 years ago
9. Pick the best example of Newton's Second Law in action.
madreJ [45]

Answer:

A rocket taking off from earth which pushes gasses in one direction and the rocket in

the other

7 0
3 years ago
A psychopathologist records the number of criminal offenses among teenage drug users in a nationwide sample of 1,201 participant
lara [203]

Answer:

Standard deviation = 3

Explanation:

Given

N = 1201

SS = 10800

Required

Determine the standard deviation

First, we need to determine the variance;

Variance = \frac{SS}{N - 1}

This gives:

Variance = \frac{10800}{1201 - 1}

Variance = \frac{10800}{1200}

Variance = 9

Know that:

Variance = SD^2

Where SD represents standard deviation

This gives

9 = SD^2

Take square root

SD = \sqrt 9

SD = 3

7 0
3 years ago
The force experienced by a unit test charge is a measure of the strength of an electric:
Flauer [41]

an electric field is the answer

3 0
3 years ago
Read 2 more answers
Consider a venturi with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.
Marina CMI [18]

Answer:

(P_1-P_2)=1913.31 N/m^2

Explanation:

given:

\frac{A_t}{A_1}=0.85

V_1=90 m/s

γ∞=1.23 kg/m^3

solution:

since outside pressure is atm pressure vaccum can be defined by (P_1-P_2)

V_1=√2(P_1-P_2)/γ∞[\frac{A_t}{A_1}^2-1]

(P_1-P_2)=1913.31 N/m^2

6 0
2 years ago
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