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Sergio [31]
3 years ago
9

Which of the following is a result of gravitational forces in the Solar System?

Physics
1 answer:
postnew [5]3 years ago
3 0
The correct answer is d
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Pls help waves for physics
djverab [1.8K]

Answer:

b) 252 Hz or 260 Hz

c) 0.25 s

Explanation:

b) The frequency of the beats is 4 Hz, and one tuning fork has a frequency of 256 Hz.  Therefore, the second tuning fork is either 4 Hz lower or 4 Hz higher.

f = 252 Hz or 260 Hz

c) Period is the inverse of frequency.

T = 1/f

T = 1 / (4 Hz)

T = 0.25 s

8 0
3 years ago
Why is gravitational acceleration almost always a factor in determining pressure?
Scorpion4ik [409]

Explanation:

Newton's law of universal gravitation states that every object attracts every other object with a force. For any two objects, this force is directly proportional to the mass of each object. The greater the masses, the greater the force of attraction between them. Newton also deduced that this force decreases as the square of the distance between the centers of the objects increases. The farther away the objects are from each other, the less the force of attraction between them.

7 0
3 years ago
Pls help i will give u brainliest!
Ivan

Answer: B.

Explanation:

4 0
3 years ago
The electric field at the center of a ring of charge is zero. At very large distances from the center of the ring along the ring
Daniel [21]

Answer:

z = 1.16m

Explanation:

The electric field in a point of the axis of a charged ring, and perpendicular to the plane of the ring is given by:

E_z=\frac{Qz}{(z^2+r^2)^{\frac{3}{2}}}

z: distance to the plane of the ring

r: radius of the ring

Q: charge of the ring

you have that:

E_{z->0} = 0

E_{z->∞} = 0

To find the value of z that maximizes E you use the derivative respect to z, and equals it to zero:

\frac{dE_z}{dz}=Q[\frac{1}{(z^2+r^2)^{3/2}}+z(-\frac{3}{2})\frac{1}{(z^2+r^2)^{5/2}}(2z)]=0\\\\(z^2+r^2)^{5/2}=3z^2(z^2+r^2)^{3/2}\\\\(z^2+r^2)^2=3z^4\\\\z^4+2z^2r^2+r^4=3z^4\\\\2z^4-2z^2r^2-r^4=0\\\\z^2_{1,2}=\frac{-(-2)+-\sqrt{4-4(2)(-1)}}{2(2)}=\frac{2\pm 3.464}{4}\\\\

you take the positive value:

z^2=\frac{2+3.464}{4}=1.366\\\\z=1.16m

hence, the distance in which the magnitude if the electric field is maximum is 1.16m

7 0
3 years ago
2) An airplane flies with a velocity v1=90 m/s to the west, but there is a crosswind of v2=40 m/s to the south.
julsineya [31]
The magnitude will be =23.94 WS and the direction will be =98.48 m/s
6 0
3 years ago
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