Answer:
a. 2.0secs
b. 20.4m
c. 4.0secs
d. 141.2m
e. 40m/s, ∅= -30°
Explanation:
The following Data are giving
Initial speed U=40m/s
angle of elevation,∅=30°
a. the expression for the time to attain the maximum height is expressed as

where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at

b. the expression for the maximum height is expressed as

c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,
Hence T=2t
T=2*2.0
T=4.0secs
d. The range of the projectile is expressed as

e. The landing speed is the same as the initial projected speed but in opposite direction
Hence the landing speed is 40m/s at angle of -30°
Explanation:V.R of a lever is 3 means effort distance of the lever is 3 times more than the effort distance of the load. ... Efficiency of a lever is 60% means 40% of the energy is wasted due to friction as no machine is Friction less.
If you can get a clearer image, I would be able to complete most, if not, all problems on the paper.
Answer:

Explanation:
The energy contained per second in the fuel is:


It is know that fission of a gram of uranium liberates
. Mass flow rate is computed herein:


The needed quantity of fuel per second is:


The annual fuel consumption is now obtained:


The cost of fuel for the lifetime of the plant is:

I'd just keep in mind the relationships for: g = 9.81 m/s²
<span>and universal gravitational acceleration: </span>
<span>ie that: </span>
<span>for MASS, its directly proportional: </span>
<span>a mass that is 0.815 of Earth's would have a gravitational acceleration that's: </span>
<span>0.815g </span>
<span>and </span>
<span>for RADIUS (R) of planet, it's inversely proportional to the square of R </span>
<span>a planet with radius that's 0.949 of Earth's would have a gravitational acceleration of: </span>
<span>(1/0.949)² = 1.11g </span>
<span>the combination of these two effects would be: </span>
<span>(0.815 • 1.11)g = 0.905g = 8.88 m/s²</span>