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Andrews [41]
3 years ago
15

When a wave propagates through a medium the molecules of the medium?

Physics
1 answer:
Maurinko [17]3 years ago
5 0
The molecules of the medium move back and forth in response to the wave.
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The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the
Airida [17]

Answer:

\frac{I}{I_0}=113.68

Explanation:

P = Acoustic power = 63 µW

r = Distance to the sound source = 210 m

Acoustic power

P=IA\\\Rightarrow I=\frac{P}{A}\\\Rightarrow I=\frac{63\times 10^{-6}}{4\times \pi \times 210^2}

Threshold intensity = I_0=1\times 10^{-12}\ W/m^2

Ratio

\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

6 0
2 years ago
The density of silver is 10.5 g cm3. a piece of silver with a mass of 61.3 g would ovvupy a volume of ?
natali 33 [55]
The relationship between mass m, volume V and density d is:
d= \frac{m}{V}
The silver has density d=10.5 g/cm^3, and the mass of the piece of silver is m=61.3 g. Therefore we can calculate its volume using the previous formula:
V= \frac{m}{d}= \frac{61.3 g}{10.5 g/cm^3}=5.84 cm^3
7 0
2 years ago
Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 39.9° wit
wariber [46]

Answer:

n=2.053

Explanation:

We will use Snell's Law defined as:

n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}

Where n values are indexes of refraction and \theta values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:

1*Sin(39.9)=n_{2}*Sin(18.2)

Solving for n_{2} yields:

n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053

Remember to use degrees for trigonometric functions instead of radians!

6 0
3 years ago
The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable
Ann [662]

I attached a free body diagram for a better understanding of this problem.

We start making summation of Moments in A,

\sum M_A = 0

P(6cos\theta)-981(4cos\theta)=0

P=654N

Then we make a summation of Forces in Y,

\sum F_y = 0

654+R-981 = 0

R=327N

At the end we calculate the angle with the sin.

sin\theta = \frac{3m}{4m+2m+2m} = \frac{3m}{8m}

\theta = 22.02\°

8 0
3 years ago
Consider a system of two particles: ball A with a mass m is moving to the right a speed 2v and ball B with a mass 3m is moving t
arlik [135]

Answer:

Explanation:

Answer:

Explanation:

Given that,

System of two particle

Ball A has mass

Ma = m

Ball A is moving to the right (positive x axis) with velocity of

Va = 2v •i

Ball B has a mass

Mb = 3m

Ball B is moving to left (negative x axis) with a velocity of

Vb = -v •i

Velocity of centre of mass Vcm?

Velocity of centre of mass can be calculated using

Vcm = 1/M ΣMi•Vi

Where M is sum of mass

M = M1 + M2 + M3 +...

Therefore,

Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb

Rearranging for better understanding

Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)

Vcm = (m•2v + 3m•-v) / (m + 3m)

Vcm = (2mv — 3mv) / 4m

Vcm = —mv / 4m

Vcm = —v / 4

Vcm = —¼V •i

3 0
3 years ago
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