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4 years ago

To increase the current in a circuit, the BLANK can be increased. HELP ASAP

Physics

2 answers:

Vesna [10]4 years ago

5 0

Answer:

that would be voltage

sladkih [1.3K]4 years ago

3 0

Voltage is your answer

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Which of the following represents a concave lens?<br> A. -di<br> B. +di<br> C. -f<br> D. +f

Nina [5.8K]

Answer:

The answer is option D. +f

4 0

3 years ago

Read 2 more answers

You are using a small telescope to view two closely spaced light bulbs located a mile away. Each light bulb is emitting blue lig

Juliette [100K]

Answer:

Explanation:

The problem is based on resolving power of instruments . Resolving power of instruments is related to wavelength of light as follows

resolving power of telescope ∝ 1 / λ

Higher the resolving power closer the object that can be looked separately.

Wave length of blue light is shorter than that of red light so resolving power in case of blue light will be higher. So we have better chance of distinguishing separate bulbs when color light is blue.

5 0

4 years ago

Puck 1 (1 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (1 kg) which is initially at rest. After th

Burka [1]

Answer:

Explanation:

Parameters given:

Mass of Puck 1, m = 1 kg

Mass of Puck 2, M = 1 kg

Initial velocity of Puck 1, u = 20 m/s

Initial velocity of Puck 2, U = 0 m/s

Final velocity of Puck 1, v = 5 m/s

Since we are told that momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum of the system = Total final momentum of the system

mu + MU = mv + MV

(1 * 20) + (1 * 0) = (1 * 5) + (1 * V)

20 = 5 + V

V = 20 - 5 = 15 m/s

Puck 2 moves with a velocity of 15 m/s

7 0

3 years ago

A particle moves along the x axis. Its position is given by the equation

krok68 [10]

The position of the particle when it changes direction is x = 3.0 m

Explanation:

The position of the particle is given by the equation

$x(t)=2.4+2.9t-3.5t^2$

In order to determine its position when it changes direction, we need to find the time t at which the velocity of the particle becomes zero.

The velocity of the particle si given by the derivative of the position, therefore:

$v(t)=\frac{dx}{dt}=2.9-2\cdot 3.5t^{2-1}=2.9-7t$

The velocity is zero when:

$v(t)=0=2.9-7t\\7t=2.9\\t=\frac{2.9}{7}=0.41 s$

And therefore, the position at t = 0.41 s is

$x(0.41)=2.4+2.9(0.41)-3.5(0.41)^2=3.0 m$

Learn more about position and velocity:

brainly.com/question/5248528

#LearnwithBrainly

3 0

4 years ago

PLEASE HELP ASAP.

julia-pushkina [17]

First of all, let's write the density of water (W) and the density of alcohol (A):
$d_W = 1000 kg/m^3$
$d_A = 789 kg/m^3$
And the relationship between density d, mass m and volume V:
$d= \frac{m}{V} (1)$
The density of the mixture water+alcohol is 900 kg/m^3. The mass of this mixture is the sum of the masses of water and alcohol, and the volume of this mixture is the sum of the volumes of water and alcohol. So we can write
$d_T = 900 kg/m^3 = \frac{m_W +m_A}{V_W+V_A}$ (2)
Now let's solve the two parts of the problem.

a) Let's rewrite (2) by replacing the volumes with $V= \frac{m}{d}$ :
$900 kg/m^3 = \frac{m_W+m_A}{ \frac{m_W}{1000 }+ \frac{m_A}{789} }$
By solving this equation, we find:
$\frac{m_A}{m_W}= \frac{0.1}{0.14}=0.71$
This means that there are 0.71 kg of alcohol per each kg of water in the mixture.

b) Similarly, let's rewrite (2) by replacing the masses with $m=dV$ :
$900 kg/m^3 = \frac{1000 V_W+789 V_A}{V_W+V_A}$
Re-arranging and solving, we find
$\frac{V_A}{V_W}= \frac{100}{111}=0.90$
This means that there are 0.90 L of alcohol per each liter of water in the mixture.

3 0

3 years ago