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alexdok [17]
3 years ago
9

F(x) = 5/(7x-8) What is the inverse of this function?

Mathematics
2 answers:
oee [108]3 years ago
3 0
f(x)=\dfrac{5}{7x-8}\\\\y=\dfrac{5}{7x-8}\iff\dfrac{1}{y}=\dfrac{7x-8}{5}\ \ \ |multiply\ both\ sides\ by\ 5\\\\\dfrac{5}{y}=7x-8\ \ \ |add\ 8\ to\ both\ sides\\\\7x=\dfrac{5}{y}+8\\\\7x=\dfrac{5}{y}+\dfrac{8y}{y}\\\\7x=\dfrac{5+8y}{y}\ \ \ \ |divide\ both\ sides\ by\ 7\\\\x=\dfrac{5+8y}{7y}\\\\Answer:\boxed{f^{-1}(x)=\dfrac{5+8x}{7x}\ other\ form\ f^{-1}(x)=\dfrac{5}{7x}+\dfrac{8}{7}}
zzz [600]3 years ago
3 0
f(x)=\dfrac{5}{7x-8}\\
y=\dfrac{5}{7x-8}\\
7x-8=\dfrac{5}{y}\\
7x=\dfrac{5}{y}+8\\
x=\dfrac{5}{7y}+\dfrac{8}{7}\\
\boxed{f^{-1}(x)=\dfrac{5}{7x}+\dfrac{8}{7}}

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8 0
3 years ago
A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two addi
mylen [45]

Given that a polynomial function P(x) has rational coefficients.

Two roots are already given which are i and 7+8i,

Now we have to find two additional roots of P(x)=0

Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.

conjugate of a+bi is given by a-bi

So using that logic, conjugate of i is i

also conjugate of 7+8i is 7-8i

Hence final answer for the remaining roots are (-i) and (7-8i).

5 0
3 years ago
Can I get help please someone
Kamila [148]

Answer:

Step-by-step explanation:

Im pretty sure its A

4 0
3 years ago
Read 2 more answers
Ok can someone please help me? 15 pts
Citrus2011 [14]

Answer:

3.2

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12.8/4 which makes the answer 3.2

7 0
3 years ago
$35,125 loan, a feat which took ten years of quarterly payments. The loan had an interest rate of 7.44%, compounded quarterly. I
Darya [45]
First find the amount of each payment:
35,125 = P(\frac{(1+i)^{40} -1}{i (1+i)^{40}}) , i = \frac{.0744}{4}  \\  \\ P = 1252.70

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The percentage is the service charge divided by total cost:
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7 0
3 years ago
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