Step-by-step explanation:
let x represent the bus
6x + 21 = 195
6x = 195 - 21
6x =174
x = 29
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
To find the mean, add the numbers, and divide by the amount of numbers there is.
(82 + 105 + 247 + 119 + 94 + 202)/6
Simplify. Remember to follow PEMDAS. First, add
(849)/6
Next, divide by 6
849/6 = 141.5
141.5 should be your answer
hope this helps
The domain is the set of x-values of a function. The range is the set of y-values of a function.
You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31
2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25
3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16
4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13
5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1
The range is {31, 25, 16, 13, 1}.
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Answer: {31, 25, 16, 13, 1}
