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tia_tia [17]
4 years ago
9

Who helps recycle nutrients through an ecosystem? A. producers and decomposers B. producers and consumers C. consumers and decom

posers D. producers, consumers, and decomposers
Chemistry
2 answers:
s2008m [1.1K]4 years ago
8 0

D. Producers im sure of it hope im right

Nonamiya [84]4 years ago
3 0
<h2>Answer:</h2>

The correct answer is option A which is producers and decomposers.

<h3>Explanation:</h3>
  • In the food chain of an ecosystem, Producers are the organism which make food taking nutrients from soil and energy from sun like plants.
  • Consumers are organism which consume this food by plants like animal.
  • And decomposers are organism which convert complex food materiel into simple one like bacteria.
  • As recycling is the use and reuse of material in ecosystem.
  • Hence decomposers and producer are using materials again and again with the help of each other.
  • So they both are helping in recycle of materials in ecosystem.
You might be interested in
Write a short note on a simple microscope​
Annette [7]

Answer:

A simple microscope is one that uses a single lens for magnification, such as a magnifying glass while a compound microscope uses several lenses to enhance the magnification of an object. It uses a lens to enlarge an object through angular magnification alone, giving the viewer an erect enlarged virtual image.

If its wrong correct me.

7 0
4 years ago
Which of the following is not true about limiting and excess reagents?
Bogdan [553]

Answer : The incorrect option is, (d) The reactant that was the smallest given mass is the limiting reagent.

Explanation :

Limiting reagent : It is the reagent that is completely consumed in the chemical reaction when the chemical reaction is complete. No amount is left after the reaction is complete. The amount of product obtained is determined by the limiting reagent. A balanced equation is necessary to determine which reactant is limiting reagent.

Excess reagent : It is the reagent that are not completely consumed in the chemical reaction. That means the reagent is in excess amount. Some amount of the excess reagent is left over after the reaction is complete.

From this we conclude that the options, A, B and C are correct. While the option D is incorrect.

Option D is incorrect because it is not necessary the reactant that was the smallest given mass is the limiting reagent but it is judge by the number of moles present in the reaction.

Hence, the incorrect option is, (d)

4 0
3 years ago
For each of the reactions, calculate the mass (in grams) of the product formed when 15.12g of the underlined reactant completely
Ludmilka [50]

Answer:

Part A : amount of product (KCl) =  28.88 g

Part B :  amount of product (KBr) =  46.13 g

Part C : amount of product (Cr₂O₃) =  17.3 g

Part D: amount of product (SrO) =  35.76 g

Explanation:

Part A:

Data Given:

Reaction :

                      2K(s) + Cl₂(g) --------> 2KCl

Amount of underline Reactant  (K) = 15. 12g

amount of other reactant = more than enough

Explanation:

As the Potassium (K) is 15.12g and other reactant that is chlorine is more than enough so the K is limiting reagent.

So, amount of product depend on the amount of Potassium (K)

Now Look at Given Reaction:

                                2K(s) + Cl₂(g) --------> 2KCl

                                2mol    1mol                 2mol

it shows that

2 mole of K give 2 mole of  KCl

if we represent mole in grams

Then

Molar mass of K = 39 g/mol

Molar mass of KCl = (39 + 35.5)

Molar mass of KCl = 74.5 g/mol

So the look again to reaction in terms of grams

                                      2K(s)     +    Cl₂(g) --------> 2KCl

                            2mole (39 g/mol)                      2mole (74.5 g/mol)

                                      78 g                                  149 g

Apply the Unity formula

                          78 g of Potassium ≅ 149 g of KCl

Then

                        15.12 g of Potassium ≅ how many g of Product (KCl)

By doing cross multiplication

               X g of Product (KCl) = 149 g of KCl  x 15.12 g of K /  78 g of K

              X g of Product (KCl) = 149 g of KCl  x 15.12 g of K /  78 g of K

              X g of Product (KCl) = 28.88 g

So the amount of product (KCl) =  28.88 g

_________________________________________

Part B:

Data Given:

Reaction :

                      2K(s) + Br₂(g) --------> 2KBr

Amount of underline Reactant  (K) = 15. 12g

amount of other reactant = more than enough

Explanation:

As the Potassium (K) is 15.12g and other reactant that is Bromine is more than enough so the K is limiting reagent.

So, amount of product depend on the amount of Potassium (K)

Now Look at Given Reaction:

                                2K(s) + Br₂(g) --------> 2KBr

                                2mol    1mol                 2mol

it shows that

2 mole of K give 2 mole of  KBr

if we represent mole in grams

Then

Molar mass of K = 39 g/mol

Molar mass of KBr = (39 + 80)

Molar mass of KBr =  119 g/mol

So, look again to reaction in terms of grams

                                      2K(s)     +    Br₂(g) --------> 2KBr

                            2mole (39 g/mol)                      2mole (119 g/mol)

                                      78 g                                  238 g

Apply the Unity formula

                          78 g of Potassium ≅  238 g of KBr

Then

                        15.12 g of Potassium ≅ how many g of Product (KBr)

By doing cross multiplication

               X g of Product (KBr) = 238 g of KBr  x 15.12 g of K /  78 g of K

              X g of Product (KBr) = 238 g of KBr  x 15.12 g of K /  78 g of K

              X g of Product (KBr) = 46.13 g

So the amount of product (KBr) =  46.13 g

__________________________________________

Part C:

Data Given:

Reaction :

                      4Cr(s) + 3O₂(g) --------> 2Cr₂O₃

Amount of underline Reactant  (Cr) = 15. 12g

amount of other reactant = more than enough

Explanation:

As the Chromium (Cr) is 15.12g and other reactant that is Oxygen is more than enough so the Cr is limiting reagent.

So, amount of product depend on the amount of Chromium (Cr)

Now Look at Given Reaction:

                                  4Cr(s) + 3O₂(g) --------> 2Cr₂O₃

                                  4mol      3mol                 2mol

it shows that

4 mole of Cr give 2 mole of  Cr₂O₃

if we represent mole in grams

Then

Molar mass of Cr = 52 g/mol

Molar mass of 2Cr₂O₃ = 2 [2 (52) + 3(16) ] = 2 (104+ 48)

Molar mass of  2Cr₂O₃ =  304 g/mol

So, look again to reaction in terms of grams

                                     4Cr(s) + 3O₂(g) --------> 2Cr₂O₃

                                 4 mol (52 g/mol)              2 mole (304 g/mol)

                                      208 g                                  608 g

Apply the Unity formula

                          208 g of Chromium ≅  608 g of Cr₂O₃

Then

                        15.12 g of Chromium ≅ how many g of Product (Cr₂O₃)

By doing cross multiplication

        X g of Product (Cr₂O₃) = 238 g of Cr₂O₃  x 15.12 g of Cr /  208 g of Cr

        X g of Product (Cr₂O₃) = 238 g of Cr₂O₃  x 15.12 g of Cr /  208 g of Cr

        X g of Product (Cr₂O₃) = 17.3 g

So the amount of product (Cr₂O₃) =  17.3 g

________________________________________

Part D:

Data Given:

Reaction :

                      2Sr(s) + O₂(g) --------> 2SrO(s)

Amount of underline Reactant  (Sr) = 15. 12g

amount of other reactant = more than enough

Explanation:

As the Strontium (Sr) is 15.12g and other reactant that is Oxygen is more than enough so the Sr is limiting reagent.

So, amount of product depend on the amount of Strontium (Sr)

Now Look at Given Reaction:

                                    2Sr(s) + O₂(g) --------> 2SrO(s)

                                    2mol      1mol              2mol

it shows that

2 mole of Sr give 2 mole of SrO

if we represent mole in grams

Then

Molar mass of Sr = 87.6 g/mol

Molar mass of 2SrO = 2 [87.6 + 16] = 2 (103.6)

Molar mass of 2SrO =  207.2 g/mol

So, look again to reaction in terms of grams

                                      2Sr(s) + O₂(g) --------> 2SrO(s)

                                 2 mol ( 87.6 g/mol)         2 mole (207.2 g/mol)

                                      175.2 g                                  414.4 g

Apply the Unity formula

                          175.2 g of Strontium ≅  414.4 g of SrO

Then

                        15.12 g of Strontium ≅ how many g of Product (SrO)

By doing cross multiplication

       X g of Product (SrO) = 414.4 g of SrO  x 15.12 g of Sr /  175.2 g of Sr

        X g of Product (SrO) = 414.4 g of SrO  x 15.12 g of Sr /  175.2 g of Sr

        X g of Product (SrO) = 35.76 g

So the amount of product (SrO) =  35.76 g

8 0
3 years ago
Element X has an electron configuration that ends with 5p6. Which of the following describes this atom correctly?
pishuonlain [190]
The answer is d noble gas because the very last column on the periodic table is all the noble gases
7 0
4 years ago
Suppose 0.09886 M KOH is titrated into 15.00 mL H2SO4 of unknown concentration until the equivalence point is reached. It takes
AleksAgata [21]

Answer:0.00028917

Explanation:

8 1
3 years ago
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