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tia_tia [17]
4 years ago
9

Who helps recycle nutrients through an ecosystem? A. producers and decomposers B. producers and consumers C. consumers and decom

posers D. producers, consumers, and decomposers
Chemistry
2 answers:
s2008m [1.1K]4 years ago
8 0

D. Producers im sure of it hope im right

Nonamiya [84]4 years ago
3 0
<h2>Answer:</h2>

The correct answer is option A which is producers and decomposers.

<h3>Explanation:</h3>
  • In the food chain of an ecosystem, Producers are the organism which make food taking nutrients from soil and energy from sun like plants.
  • Consumers are organism which consume this food by plants like animal.
  • And decomposers are organism which convert complex food materiel into simple one like bacteria.
  • As recycling is the use and reuse of material in ecosystem.
  • Hence decomposers and producer are using materials again and again with the help of each other.
  • So they both are helping in recycle of materials in ecosystem.
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4 years ago
What propertys does the rock state-of -matter have that wont let Logan poke his finger through it?
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4 0
3 years ago
A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to reach the
RSB [31]

Answer:

The concentration of the borax solution is 0.1066 M

Explanation:

Step 1: Dtaa given

Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L

Molarity of H2SO4  = 1.03 M

Volume of the H2SO4 = 2.07 mL = 0.00207 L

Step 2: The balanced equation

Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O

Step 3: Calculate molarity of borax solution

b*Ca*Va = a * Cb*Vb

⇒with B = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of borax = TO BE DETERMINED

⇒with Va = the volume of borax = 0.020 L

⇒with a = the coefficient of borax = 1

⇒with Cb = the concentration of H2SO4 = 1.03 M

⇒with Vb = the volume of H2SO4 = 0.00207 L

Ca*0.020 L = 1.03 M * 0.00207 L

Ca = (1.03 * 0.00207) / 0.020

Ca = 0.1066 M

The concentration of the borax solution is 0.1066 M

6 0
4 years ago
A 2,000g of C-14 is left to decay radioactively. The half-life of Carbon-14 is approximately 5,700 years. What percentage of the
dsp73
Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
c = c₀·e∧-λ·t.
c = 2000 · e∧-(0,000121 1/y · 17100 y).
c = 252 g.
ω = 252 g ÷ 2000 g = 0,126 = 12,6%.
<span>

</span>
4 0
3 years ago
Read 2 more answers
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