Answer:
Sulfur (Option-C) <span>exhibits chemical behavior similar to that of oxygen.
Explanation:
Sulfur has same chemical properties as that of Oxygen because both of them belongs to same group in the periodic table. Also, the similarity of chemical behaviour among the group members is due to same number of electrons in their valence shells.
For examole, the electronic configuration of Oxygen is,
1s</span>², 2s², 2p⁴
There are six valence electrons in the valence shell (i.e. 2) of Oxygen.
Now for Sulfur,
1s², 2s², 2p⁶, 3s², 3p⁴
There are six valence electrons in the valence shell (i.e. 3) of Sulfur.
Therefore, both elements tends to gain 2 electrons in a reaction and form O⁻² and S⁻² respectively.
Sodium chloride and prussic acid are formed
NaCN+HCl→NaCl+HCN
Answer:
the answer is b Li + Cl2 .....
When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :
when Pka = - ㏒ Ka
6.86 = -㏒ Ka
∴Ka = 1.38 x 10^-7
by using ICE table:
H2PO4- → H+ + HPO4
initial 0.4 m 0 0
change -X +X +X
Equ (0.4-X) X X
when Ka = [H+][HPO4] / [H2PO4-]
by substitution:
1.38 X 10^-7 = X^2 / (0.4-X) by solving for X
∴X = 2.3x 10^-4
∴[H+] = X = 2.3 x 10^-4
∴PH = -㏒[H+]
= -㏒ (2.3 x 10^-4)
∴PH = 3.6
