The answer would be b) energy
Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions
Answer:
She will observe that the pressure on the tire is higher.
Explanation:
By the ideal gas law, the pressure and the temperature are directly proportional, so, if the temperature increases the pressure increases too:
PV = nRT (P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature).
The temperature is a measure of the average kinetic energy of the gas molecules, so when the temperature increases, the energy also increases, and the gas molecules will move more quickly, so they will collide more often between themselves and in the wall. Those collisions will be with more force because the velocity is higher.
So, the pressure will be higher, because it is the result of collisions of the gas molecules with the walls of the tire.
Answer : The fraction of the molecules in the neutral (imidazole) form are, 0.799
Explanation : Given,
pH = 6.6
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
...........(1)
Now we have to determine the fraction of the molecules are in the neutral (imidazole) form.
Fraction of neutral imidazole =
Now put the expression 1 in this expression, we get:
Fraction of neutral imidazole =
Fraction of neutral imidazole =
Fraction of neutral imidazole =
Fraction of neutral imidazole = 0.799
Thus, the fraction of the molecules in the neutral (imidazole) form are, 0.799
To balance it, it would be N2 + 3H2 ------> 2NH3.
for c) it would be 2N2 + 6H2 -------> 4NH3