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Tamiku [17]
3 years ago
13

Magnesium hydroxide (Mg(OH)2): g/mol

Chemistry
2 answers:
Eva8 [605]3 years ago
8 0

To determine the molar mass, you need to get the atomic mass of the molecule. To do this, check the periodic table for the atomic mass or average atomic weight of each element.

Mg = 24.305 x 1 = 24.305 amu

O = 15.9994 x 2 =31.9988 amu

H = 1.0079 x 2 = 2.0158 amu

 

Then, add all the components to get the atomic mass of the molecule.

24.305 amu + 31.9988 amu + 2.0158 amu = 58.3196 amu


The atomic mass is just equivalent to its molar mass.

So, the molar mass of Magnesium hydroxide (Mg(OH)2) is 58.3196 g/mol.

Bumek [7]3 years ago
6 0
Answer:
molar mass of Mg(OH)2 = 58.305 grams/mole

Explanation:
From the periodic table:
atomic mass of Mg = 24.305 grams
atomic mass of oxygen = 16 grams
atomic mass of hydrogen = 1 gram

Now the given compound has:
1 mole of Mg, 2 moles of oxygen and 2 moles of hydrogen
Therefore:
molar mass of Mg(OH)2 = 24.305 + 2(16) + 2(1) = 58.305 grams/mole
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yanalaym [24]

Answer: The concentration of KOH for the final solution is 0.275 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

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moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{10.0g}{56g/mol}=0.178moles

Now put all the given values in the formula of molality, we get

Molality=\frac{0.178\times 1000}{150}=1.19M

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1.19 M

V_1 = volume of stock solution = 15.0 ml

C_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 65.0 ml

Putting in the values we get:

1.19\times 15.0=M_2\times 65.0

M_1=0.275M

Therefore, the concentration of KOH for the final solution is 0.275 M

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Hey please answer this thanks.
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