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Svetach [21]
2 years ago
14

Naftalin buharlaşırsa hangi olay gerçekleşir?ACİLLLLLL!​

Chemistry
1 answer:
Eduardwww [97]2 years ago
6 0

Answer:

Turkish: Bir gaza dönüşecekler ve gaz, güveler ve güve larvaları için çok zehirlidir.

English:They will turn in to a gass and the gass is very toxic to moths and moth larvae.

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What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Andrews [41]

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

6 0
3 years ago
20cm³ of methane gas was burnt in 20cm³ of oxygen. write a balanced chemical equation for the reaction and determine which of th
solniwko [45]

Answer:

CH4 +O2 => CO2 + 2 H2O

None were in excess

Explanation:

Equation for the reaction is,

CH4 + O2 =>CO2 +2 H2O

No of moles of CH4 = (20 /1000)/24 =0.02 /24 = 0.00083

No of moles of O2 =20 /24000 = 0.0083

CH4 : O2 = 1:1

THEREFORE

None of the gases were in excess.

7 0
3 years ago
A sodium hydroxide solution is made by mixing 8.70 g NaOH with 100 g of water. The resulting solution has a density of 1.087 g/m
Ahat [919]

Answer:

Mass fraction = 0.08004

Mole fraction = 0.0377

Explanation:

Given, Mass of NaOH = 8.70 g

Mass of solution = 8.70 + 100 g = 108.70 g

Mass\ fraction\ of\ NaOH=\frac {8.70}{108.70} = 0.08004

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{8.70\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 0.2175\ mol

Given, Mass of water = 100 g

Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{100\ g}{18.0153\ g/mol}

Moles\ of\ water= 5.5508\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ NaOH=\frac {n_{NaOH}}{n_{NaOH}+n_{water}}

Mole\ fraction\ of\ NaOH=\frac {0.2175}{0.2175+5.5508}=0.0377

3 0
3 years ago
In Denver, Colorado the elevation is about 5,280 feet above sea level. Explain what potential effects this may have on the solub
Colt1911 [192]

Answer:

The solubility of the gaseous solute decreases

Explanation:

As we know, pressure decreases with altitude. This means that, at higher altitudes, the pressure is much lower than it is at sea level.

The solubility of a gas increases with increase in pressure and decreases with decrease in pressure.

Hence, in Denver, Colorado where the elevation is about 5,280 feet above sea level, a gaseous solute is less soluble than it is at sea level due to the lower pressure at such high altitude.

4 0
3 years ago
A chemist combines ethane and chlorine with the goal of producing chloroethane which other product could be reasonably expected
lesya692 [45]
<span>So when the chemist combines Ethane (CH3CH3) and Chlorine (Cl2) with the intention of producing Chloroethane (CH3CH2Cl), the other product that's formed in this reaction is 1,2-dichloroethane (ClCH2CH2Cl) also called as Ethylene dichloride with molecular weight of 98.954 g/mol. This is a colorless oily flammable substance that weighs heaver when vaporized.</span>
5 0
3 years ago
Read 2 more answers
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